33.33 meters per second.
30,000 metres or 30km
120 km/hr (1000 meters/1 km)(1 hr/60 minutes) = 2000 meters per minute ---------------------------------
Acceleration = (change in speed) / (time for the change)= (10 - 25) / 240 = -15/240 = -0.0625 meter/sec2The acceleration is negative, which is a description of slowing down.
Completely ignore the first train.The second train passes the pole in 8sec.In this 8 seconds the train drove 120 meters.So the train has a speed of 15meters per second (120/8=15).Answer: 15 (meters / second) = 54 km/h
a high speed train travels south for 2.00 h for a distance of 454km. what is its average velocity?
120 km per hour = 33.33 meters per second.
41m/s
Average acceleration over an interval of time = (final speed - initial speed) / (time for the change)= [ (0 - 30) / 1 ] (meters / second-minute) = [ (0 - 30) / (60) ] (meters / second-second) =-0.5 meter / sec2
At 200 mph, the train is moving at 293.3 feet per second.
(120 km/h) x (1000m/ 1km) x (1hour/ 3600seconds) = 33.3 m/s
454 km
33.3km/sec
33,055m or 33.055Km
30,000 metres or 30km
40 x 10 x 6 = 2400
A normal train usually travels at a speed of 100mph.
120 km/hr (1000 meters/1 km)(1 hr/60 minutes) = 2000 meters per minute ---------------------------------