120 km/hr (1000 meters/1 km)(1 hr/60 minutes)
= 2000 meters per minute
---------------------------------
33.33 meters per second.
18 kilometers per hour.
30,000 metres or 30km
a high speed train travels south for 2.00 h for a distance of 454km. what is its average velocity?
The passanger train had traveled 216000 meters by the end of this minute
41m/s
Average acceleration over an interval of time = (final speed - initial speed) / (time for the change)= [ (0 - 30) / 1 ] (meters / second-minute) = [ (0 - 30) / (60) ] (meters / second-second) =-0.5 meter / sec2
If a train that goes 500 meters every 10 seconds you will cover 30,000 meters in 10 minutes. <><><> There are 6 units of 10 seconds to a minute. 6x500= 3000 meters per minute. X 10 minutes= 30,000
120 Kilometres = 120,000 metres There are 60 minutes in an hour 120,000 divided by 60 = 2,000 2,000 metres per minute (or 2 Kilometres per minute)
33.33 meters per second.
The train travels 150m in 10seconds, Therefore it travels 900m in 1 minute and thus 54000 metres in 1 hour. The train's speed is therefore 54 kph (kilometres per hour)
18 kilometers per hour.
800 meters
454 km
120 km per hour = 33.33 meters per second.
33,055m or 33.055Km
120 km/hr *1000 m/km * 1 hour/60 minutes * 1 minute/60 seconds = 33.333... m/sec