Km/hr to m/s = 5/18
Speed60 km/hr
Cross pole in 9sec
Length=speed*time
Speed =60*5/18=50/3m/s
50/3*9=150
Length of the train =150
A.120 metres
B.180 metres
C.324 metres
D.150 metres
After the nose of the train reaches the platform, it takes some number of seconds for thenose to reach the far end. At that time, the whole train is lined up with the whole platform.Then after that, it takes the same number of seconds again for the caboose to reach the far end,and the train to completely clear the platform.So the total time that there's some overlap between the train and platform is twice the timethe train takes to move the length of the platform, which is also the length of the train.Distance = (speed) x (time)180 meters = (speed) x (9 seconds)speed = (180/9) = 20 meters per second
A train 108 m long moving at a speed of 50 kmph crosses a train 112 m long coming from the opposite direction in 6 seconds. The speed of the second train is
Frequency (1/seconds) x Wave Length (meters) = Speed (meters/sec. or m/s)
Please use the formula: distance = speed x time If you have length in miles and speed in miles per hour, if you solve for time you will get the time in hours. You can then convert that to seconds.
s=d/ts= 100 / 12s= 8.33ms-1
The answer is 72Km/hr
3.5 SECONDS
After the nose of the train reaches the platform, it takes some number of seconds for thenose to reach the far end. At that time, the whole train is lined up with the whole platform.Then after that, it takes the same number of seconds again for the caboose to reach the far end,and the train to completely clear the platform.So the total time that there's some overlap between the train and platform is twice the timethe train takes to move the length of the platform, which is also the length of the train.Distance = (speed) x (time)180 meters = (speed) x (9 seconds)speed = (180/9) = 20 meters per second
you have to know the wave length.
Use the formula: Speed = distance / time. If you divide meters / seconds, the speed will obviously be in meters/second.
Assume Length of the train =x metre,speed be y metre/ sec Time taken to cross the pole x/y sec Time taken to cross the platform=length of train+length of platform/ speed of train x/y=15 x=15y x+100/y=25 15y+100=25y 10y=100 Y=10 metre/ sec x=15y = 100
11.875 m/s
Simply horse racing is the sport of running horses at speed and the one who crosses the finishing post first is the winner.
Simply horse racing is the sport of running horses at speed and the one who crosses the finishing post first is the winner.
A train 108 m long moving at a speed of 50 kmph crosses a train 112 m long coming from the opposite direction in 6 seconds. The speed of the second train is
Since length is measured in meters, and time in seconds, it follows that speed is measured in meters/second.
The average speed of the runner is 1500m/(180 + 49.67) seconds = 6.531 m/s or 13 knots.