92 x 4 = 368 368 + 85 = 453 453/5 = 90.6 is your average for all 5 tests
Simi's tests so far can be expressed as 320 percent divided by four. To average 84 percent, she would need five times 84 or 420 percent. The difference is 100%. Assuming all the tests are equally weighted, she needs 100% on the 5th test.
(81 + 77 + 83 + 75 + X) divided by 5 = 80 average 316 + X = 400 X = 84
There are different possible ways: - Eight four point four five five - Eighty-four point four five five - Eighty-four and four hundred fifty-five thousandths.
I'll bite: False. Four is four-fifths of five.
You take four thousand one hundred twenty average. by sayid and ahmed
78
Simi's tests so far can be expressed as 320 percent divided by four. To average 84 percent, she would need five times 84 or 420 percent. The difference is 100%. Assuming all the tests are equally weighted, she needs 100% on the 5th test.
If her average over five tests is 88 then her total is 440 The most she could have scored on each of the other four tests is 100 - 400 in total, leaving 40 as the minimum from the last. Proof - we have awarded her 100 in four tests and 44 in the last - if she only got 43 in the last then on one of the others she would have to have scored 101 - but that's not possible.
The arithmetic mean is 79.
(81 + 77 + 83 + 75 + X) divided by 5 = 80 average 316 + X = 400 X = 84
No one has yet scored six, but four players have each scored five: Andy Cole, Alan Shearer, Jermain Defoe and Dimitar Berbatov.
Four to five feet.
99.94. He needed four, just four, runs in his last ever Test innings to end with an average of over 100, but he was out for 0.
A four to five member family.
between four feet and nine inches & five feet and four inches
Gavaskar scored double centuries in tests four times . They are as :220 vs west indies205 vs west indies221 vs west indies236 vs west indies
Four to five years on average.