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1/32 of the original amount.
That would depend on the original principal (the amount you borrowed) and how they compute interest.
The amount of material left in radioactive decay is an exponential function. Therefore, the way you solve this is to write it as an exponential function; for example: f = e-kt, where "f" is the fraction remaining after a certain time, "t" is the time in any unit you choose (for example, years), and "k" is a constant you have to find out. Replace the numbers you know (for t = 1600 years, f = 1/2, since 1/2 of the original remains), and solve for "k". Then, write the equation again, this time with the constant "k" you figured out before, and the time (365 years). This will give you the fraction left after that amount of time.
40 years
The half-life of Co-60 is 5.27 years. The time interval is 104.7 min = 0.0002 years approx which is 0.000038 half lives. So amount left = 9.9997 mg, approx.
10.6 years
After twice the half-life, 1/4 of the original amount remains. After 3 times the half-life, 1/8 of the original amount remains. Etc.
8 years or 80,000 miles.
1/32 of the original amount.
The half-life of 27Co60 is about 5.27 years. 15.8 years is 3 half-lives, so 0.53 or 0.125 of the original sample of 16 g will remain, that being 2 g.
The half life of Tritium is 12.32 years. it would therefore take 24.64 years for the amount to fall to a quarter of the original.
The equation for half-life is ... AT = A0 2 (-T/H) ... where A0 is the starting activity, AT is the activity at some time T, and H is the half-life, in units of T. 55134Cs has a half-life of 2.0652 years. Plugging in the known values, we get ... AT = 5.8 2 (-11.5/2.0652) AT = 5.8 2 -5.5685 AT = 0.12222
Of Course It Does as it is the hair one was born with - once this is shed the actual texture is reveal - the remnants of the original texture remain on some adults for years ( hairline, nape ) if they allow it to remain untouched
8.4
Carbon has a half life of 5730 years. That means that after 5730 years there'll only be half the amount left. After about 11500 there will be a quarter of the original. After 75000 years there will be about 0.0001 of the original sample which is too small to date accurately?
Since the half-life of cesium-137 is about 30 years, 3 half-lives would have passed in 90 years. The first half-life would leave .5 mg of cesium-137. The second would leave .25 mg, and the third half-life would leave .175 mg of cesium-137.
No, judgments remain on a credit report for seven years. Some types of judgments are renewable and therefore can remain on a report an indefinite amount of time. If you are willing to pay a fine, why not just pay the judgment?