1/32 of the original amount.
That would depend on the original principal (the amount you borrowed) and how they compute interest.
Plutonium-239 has a half-life of about 24,100 years, meaning it takes that long for half of a sample to decay. In 43 years, which is much shorter than the half-life, only a tiny fraction of the plutonium would decay. Therefore, after 43 years, approximately 99.83 grams of the original 100-gram sample would remain.
The amount of material left in radioactive decay is an exponential function. Therefore, the way you solve this is to write it as an exponential function; for example: f = e-kt, where "f" is the fraction remaining after a certain time, "t" is the time in any unit you choose (for example, years), and "k" is a constant you have to find out. Replace the numbers you know (for t = 1600 years, f = 1/2, since 1/2 of the original remains), and solve for "k". Then, write the equation again, this time with the constant "k" you figured out before, and the time (365 years). This will give you the fraction left after that amount of time.
40 years
After 1 year, 50% of the original amount of cobalt-60 will remain. This means that 50% will decay and 50% will be left. After 4 years, 6.25% of the original amount (50% of 50%) of cobalt-60 will remain.
After 14 years, 1/16th of the original amount of cobalt-60 will remain, because 14 years is equivalent to 2.64 half-lives of cobalt-60 (14 years / 5.3 years/half-life). Each half-life reduces the amount of cobalt-60 by half, so after 2.64 half-lives, the original amount will be reduced to 1/2^2.64 which is approximately 1/16th.
8 years or 80,000 miles.
Well, isn't that a happy little question! After 28,500 years, about 1/16th of the original amount of Carbon-14 remains. It's amazing to see how nature's clockwork can show us the passage of time in such a gentle and beautiful way.
Approximately 25% of Carbon 14 would remain in charcoal burned in a primitive man's campfire after about 28,000 years. This is because Carbon 14 has a half-life of around 5,730 years, so after multiple half-lives, only a fraction of the original amount will remain.
After 100 years, half of the original sample (20 grams) will remain. After another 100 years (total 200 years), only half of that amount (10 grams) will remain.
After 15.8 years, half of the original sample of 60Co would have decayed. This means that 8 grams of the original 16 gram sample will remain unchanged after that time period.
After 6 years at a 30 percent interest rate, the total amount accumulated would be 1.30 times the original amount. This increase accounts for both the original value and the interest earned over the 6 years.
1/32 of the original amount.
Tritium has a half-life of around 12.3 years. To fall to a quarter of its original amount, it would take double the half-life, or around 24.6 years.
Approximately 25% of the Earth's original amount of 40K remains today, given that one half-life of 40K is 1.26 billion years. This means that half of the original amount decayed in 1.26 billion years, leaving behind the remaining 50%, which is now further decaying to reach 25% after 4.5 billion years.
It depends on the substance and its rate of decay. The amount remaining can be calculated using the substance's half-life and the initial amount present.