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Cobalt-60 has a half-life of approximately 5.27 years, meaning that after this period, half of the original amount will have decayed. After 14 years, which is about 2.65 half-lives, the remaining amount can be calculated using the formula: remaining amount = original amount × (1/2)^(time/half-life). Therefore, after 14 years, approximately 1/6 of the original amount of cobalt-60 will remain.
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What half-life of C14 is 5730 years. What fraction of the original C14 would you expect to be present in a fossil that is 28650 years old?
1/32 of the original amount.
How much is 5 years auto loan at 0.9 percent interest?
That would depend on the original principal (the amount you borrowed) and how they compute interest.
If you had a 100 gram sample of plutonium how much would remain in 43 years?
Plutonium-239 has a half-life of about 24,100 years, meaning it takes that long for half of a sample to decay. In 43 years, which is much shorter than the half-life, only a tiny fraction of the plutonium would decay. Therefore, after 43 years, approximately 99.83 grams of the original 100-gram sample would remain.
The half life of Radium-226 is 1600 years How many grams will remain from 5 grams after 365 years?
The amount of material left in radioactive decay is an exponential function. Therefore, the way you solve this is to write it as an exponential function; for example: f = e-kt, where "f" is the fraction remaining after a certain time, "t" is the time in any unit you choose (for example, years), and "k" is a constant you have to find out. Replace the numbers you know (for t = 1600 years, f = 1/2, since 1/2 of the original remains), and solve for "k". Then, write the equation again, this time with the constant "k" you figured out before, and the time (365 years). This will give you the fraction left after that amount of time.
The half-life of cobalt-60 is 5.3 years. If you start with 10.0 g of cobalt-60 how much will remain after 21.2 years?
To calculate the remaining amount of cobalt-60 after 21.2 years, we can use the half-life formula. Since the half-life is 5.3 years, we find the number of half-lives in 21.2 years by dividing 21.2 by 5.3, which is approximately 4.0 half-lives. After 4 half-lives, the remaining amount can be calculated as (10.0 , \text{g} \times \left(\frac{1}{2}\right)^4 = 10.0 , \text{g} \times \frac{1}{16} = 0.625 , \text{g}). Thus, 0.625 g of cobalt-60 will remain after 21.2 years.
The half-life of cobalt-60 is 5.3 years After years 1 4 of the original amount of cobalt-60 will remain?
After 1 year, 50% of the original amount of cobalt-60 will remain. This means that 50% will decay and 50% will be left. After 4 years, 6.25% of the original amount (50% of 50%) of cobalt-60 will remain.
The half life of cobalt 60 is 5.3 years After years 14 of the original amount of cobalt 60 will remain?
After 14 years, 1/16th of the original amount of cobalt-60 will remain, because 14 years is equivalent to 2.64 half-lives of cobalt-60 (14 years / 5.3 years/half-life). Each half-life reduces the amount of cobalt-60 by half, so after 2.64 half-lives, the original amount will be reduced to 1/2^2.64 which is approximately 1/16th.
How much carbon-14 would be left after 5700 years?
Carbon-14 has a half-life of approximately 5,700 years, meaning that after this period, half of the original amount of carbon-14 will have decayed. Therefore, if you start with a certain amount of carbon-14, after 5,700 years, you would have 50% of the original amount remaining. After another 5,700 years (a total of 11,400 years), 25% would remain, and so on. Thus, after 5,700 years, you would have half of the initial carbon-14 quantity left.
Is there a warranty on 2006 Chevrolet colbalt catalytic converter?
8 years or 80,000 miles.
What is the amount of carbon 14 remaining after 28500 years?
Well, isn't that a happy little question! After 28,500 years, about 1/16th of the original amount of Carbon-14 remains. It's amazing to see how nature's clockwork can show us the passage of time in such a gentle and beautiful way.
A Radio Decay Isotopes Has A Half Life Of 100 Years . A Sample Of 40 Grams Of The Isotopes Will Have A Mass Of Grams In 200 Years?
10 grams... If the half-life is 100 years, that means after 100 years, half the original mass remains. After another 100 years, the mass is halved again. 40/2=20... 20/2=10.
What fraction of Carbon 14 will remain in charcoal burned in a primitive man's campfire approximately 28000 years?
Approximately 25% of Carbon 14 would remain in charcoal burned in a primitive man's campfire after about 28,000 years. This is because Carbon 14 has a half-life of around 5,730 years, so after multiple half-lives, only a fraction of the original amount will remain.
What total mass of a 16 gram sample of 60co will remain unchanged after 15.8 years?
The half-life of 27Co60 is about 5.27 years. 15.8 years is 3 half-lives, so 0.53 or 0.125 of the original sample of 16 g will remain, that being 2 g.
What is 6 years at 30 percent?
After 6 years at a 30 percent interest rate, the total amount accumulated would be 1.30 times the original amount. This increase accounts for both the original value and the interest earned over the 6 years.
What half-life of C14 is 5730 years. What fraction of the original C14 would you expect to be present in a fossil that is 28650 years old?
1/32 of the original amount.
How many days will it take an amount of tritium to fall to a quarter?
The half life of Tritium is 12.32 years. it would therefore take 24.64 years for the amount to fall to a quarter of the original.
How much cesium Half-Life2 years would remain from a 10 G sample?
The half-life of cesium-137 is approximately 30.1 years, not 2 years. After one half-life, 5 G of the original 10 G sample would remain. After two half-lives (about 60.2 years), 2.5 G would remain, and so on. If you meant a hypothetical isotope with a 2-year half-life, after 2 years, 5 G would remain, and after 4 years, 2.5 G would remain.
