1/32 of the original amount.
That would depend on the original principal (the amount you borrowed) and how they compute interest.
The amount of material left in radioactive decay is an exponential function. Therefore, the way you solve this is to write it as an exponential function; for example: f = e-kt, where "f" is the fraction remaining after a certain time, "t" is the time in any unit you choose (for example, years), and "k" is a constant you have to find out. Replace the numbers you know (for t = 1600 years, f = 1/2, since 1/2 of the original remains), and solve for "k". Then, write the equation again, this time with the constant "k" you figured out before, and the time (365 years). This will give you the fraction left after that amount of time.
40 years
The half-life of Co-60 is 5.27 years. The time interval is 104.7 min = 0.0002 years approx which is 0.000038 half lives. So amount left = 9.9997 mg, approx.
After 1 year, 50% of the original amount of cobalt-60 will remain. This means that 50% will decay and 50% will be left. After 4 years, 6.25% of the original amount (50% of 50%) of cobalt-60 will remain.
After 28500 years, approximately 3.125% of the original amount of carbon-14 would remain in a sample.
After 14 years, 1/16th of the original amount of cobalt-60 will remain, because 14 years is equivalent to 2.64 half-lives of cobalt-60 (14 years / 5.3 years/half-life). Each half-life reduces the amount of cobalt-60 by half, so after 2.64 half-lives, the original amount will be reduced to 1/2^2.64 which is approximately 1/16th.
8 years or 80,000 miles.
Approximately 25% of Carbon 14 would remain in charcoal burned in a primitive man's campfire after about 28,000 years. This is because Carbon 14 has a half-life of around 5,730 years, so after multiple half-lives, only a fraction of the original amount will remain.
After 100 years, half of the original sample (20 grams) will remain. After another 100 years (total 200 years), only half of that amount (10 grams) will remain.
After 15.8 years, half of the original sample of 60Co would have decayed. This means that 8 grams of the original 16 gram sample will remain unchanged after that time period.
After 6 years at a 30 percent interest rate, the total amount accumulated would be 1.30 times the original amount. This increase accounts for both the original value and the interest earned over the 6 years.
1/32 of the original amount.
Tritium has a half-life of around 12.3 years. To fall to a quarter of its original amount, it would take double the half-life, or around 24.6 years.
Approximately 25% of the Earth's original amount of 40K remains today, given that one half-life of 40K is 1.26 billion years. This means that half of the original amount decayed in 1.26 billion years, leaving behind the remaining 50%, which is now further decaying to reach 25% after 4.5 billion years.
After 50 years, 1500 g of actinium-227 will have undergone approximately 2.3 half-lives (50 years / 21.772 years per half-life). This means that approximately 25% (50% decayed after 1 half-life, and 50% of the remaining amount decays after the second half-life) of the original sample will remain radioactive, so there will be around 375 g of actinium-227 remaining.