0
Well, isn't that just a happy little equation we have here! When you multiply 4k by k, you simply multiply the coefficients (4 and 1) to get 4, and then add the exponents of k, which gives you k^2. So, 4k x k equals 4k^2. Just remember, there are no mistakes in math, only happy accidents!
What else can I help you with?
How do you solve the quadratic equation x2-k-x equals 0?
2
If K 5 and (4K plus 6) 26 and (6k-2) 28 for what value of k will they have the same length?
To find the value of ( k ) for which ( 4K + 6 = 26 ) and ( 6k - 2 = 28 ), we can solve each equation. For ( 4K + 6 = 26 ): [ 4K = 20 ] [ K = 5 ] For ( 6k - 2 = 28 ): [ 6k = 30 ] [ k = 5 ] Both equations yield ( k = 5 ). Thus, when ( k = 5 ), both expressions have the same length.
What is -k - 4k?
Remember in basic Algebra we learned that all variables can be substituted as 1's If needed. So lets do that: -k - 4k = -1 - 4(1) = -5 So now we can rewrite this removing the 1's we put in: -k - 4k = -5k
What are the two possible values of k when the line y equals x plus k is a tangent to the circle x2 plus y2 equals 25?
Tangent line equation: y = x+k Circle equation: x^2 +y^2 = 25 If: y = x+k then y^2 = (x+k)^2 => y^2 = x^2 +2kx+k^2 So: x^2 +x^2 +2kx +k^2 = 25 Transposing terms and collecting like terms: 2x^2 +2kx +(k^2 -25) = 0 Using the discriminant: 4k^2 -4*2*(k^2 -25) = 0 Which is the same as: 4k^2 -8k^2 +200 = 0 Collecting like terms and subtracting 200 from both sides: -4k^2 = -200 Divide both sides by -4: k^2 = 50 Square root both sides: k = + or - the square root of 50 Therefore it follows that the possible values of k are plus or minus the square root of 50
4k-9k equals 10 What is the answer?
k=-2
How do you find the formula of infinite surds?
x =√k+√k+√k…… ectx² = k + xx² - x = kx² - x + (1/2)² = k + (1/2)² factorise x² - x + (1/2)²(x + 1/2)² = k + 1/4(x + 1/2)² = (4k + 1)/4x + 1/2 = ± √(4k + 1)/2x = 1/2 ± √(4k + 1)/2it obviously has to be positivex = 1/2 + √(4k + 1)/2x = (1 + √(4k + 1))/2
What is 4k-7 equals 7?
4k-7 = 7 4k = 14 k = 3.5 or k = 7/2
What is the answer for 31 equals 3-4k solve for k?
31 = 3-4k 31-3 = -4k 28 = -4k Divide both sides of the equation by -4 to find the value of k: k = -7
What is the value of k in the equation 8-4k equals 40?
8-4k = 40 (4k-8) - 8 = 40-8 4k = 32 4k/4 = 32/4 k =8
How do you solve the quadratic equation x2-k-x equals 0?
2
What is 4k-64?
4k-64 = -60
What does x in this equation?
wait is that algerbra? then what equaiton
Q equals 4k plus 4u solve for k?
q=4k+4uImproved Answer:-If: Q = 4k+4uThen: k = (4u-Q)/-4
How do you solve -4k-2 equals 10?
-4k-2=10 -4k=10+2 -4k=12 k=-3
What improper fractions are in between 4 and 5?
There are infinitely many of them.Take any positive integer k and let 0
If K 5 and (4K plus 6) 26 and (6k-2) 28 for what value of k will they have the same length?
To find the value of ( k ) for which ( 4K + 6 = 26 ) and ( 6k - 2 = 28 ), we can solve each equation. For ( 4K + 6 = 26 ): [ 4K = 20 ] [ K = 5 ] For ( 6k - 2 = 28 ): [ 6k = 30 ] [ k = 5 ] Both equations yield ( k = 5 ). Thus, when ( k = 5 ), both expressions have the same length.
What is -k - 4k?
Remember in basic Algebra we learned that all variables can be substituted as 1's If needed. So lets do that: -k - 4k = -1 - 4(1) = -5 So now we can rewrite this removing the 1's we put in: -k - 4k = -5k
