Alvin is 44 and Benjamin is 11.
The sum of the ages of husband and his wife is four times the sum of the ages of their children.Four years ago,the ratio of the sum of their ages of their to the sum of the ages of their children was 18:1 two years hence the ratio will be 3:1. How many children do they have.
Maria is 11 years old.
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
50
c refer to the christ in the ages of times
If Alvin is 7 years younger than Elga, then Alvin + 7 = Elga. If the sum of their ages is 87, then Alvin + Elga = 87. Substitute Alvin + 7 in the previous equation to get Alvin + (Alvin + 7) = 87. Reduce that and get 2 Alvin = 80 which means that Alvin = 40. That means that Elga = 47.
57
It is 50 years.
alvin is 9 years younger than elga the sum of there age is 53 how old is elga
Alvin +Elga = 56 3 : 1 56 รท 4 = 14 Alvin = 56 - 14 = 42 Elga = 14
Elga is 24, because this would mean that Alvin's age is 48, and 24+48=72.
It was given the name middle ages because it was the years between prehistoric times and modern times.
The ages are 8 and 4
The sum of the ages of husband and his wife is four times the sum of the ages of their children.Four years ago,the ratio of the sum of their ages of their to the sum of the ages of their children was 18:1 two years hence the ratio will be 3:1. How many children do they have.
He was different ages at different times. He was 0 years old in 1642.
Thirty Three Years Old 3 times 11 is 33. She is three times older
Maria is 11 years old.