0
A boy is b years old and his father is 6 times as old as him. Find the father and age. Find also the sum of their ages in y years' time?
Wiki User
∙ 7y ago
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
Wiki User
∙ 7y ago
Add your answer:
Earn +20 pts
A father is twelve times as old as his son and the difference in their ages is 40 years. How old is each?
son- b/t 3 and 4 dad- b/t 36 and 48
If a son is one half of his father's his age is 72 what is the sum of there ages?
108 years Father = 72 Son = 36 (1/2 of father's) 72 + 36 = 108
2 you are currently 5 times as old as your son In 6 years time you will be three times as old as he will be then What are your ages?
If x is the age of the son, then 5x would be the age of the father. In 6 years, the son would be x + 6 years old, where the father would be 3(x + 6) years old. Since the original age of the father is 5x, then in 6 years the father could also be said to be 5x + 6 years old. Setting these two expressions for the father's age as an equation, we then can solve for x, the son's age. 3(x + 6) = 5x +6 3x + 18 = 5x + 6 2x = 12 x = 6 The original age of the son is 6 and of the father (5x) is 30 years old. In 6 years, the son would be 12 and the father would be [3x + 18 or 5x + 6] 36 years old.
Which subject in 9th standard CBSE pattern?
The sum of the ages of husband and his wife is four times the sum of the ages of their children.Four years ago,the ratio of the sum of their ages of their to the sum of the ages of their children was 18:1 two years hence the ratio will be 3:1. How many children do they have.
A father's age is three times the sum of the ages of his two children find the age of the father?
Not possible to give a definitive answer without at least one more variable - there are too many possibilities ! For example:- say the children are 5 & 3 - that would make the father 24. However - if they were 5 & 2, the father would be 21 OR if they were 5 & 6, he would be 33 !
A father is 26 older than his son if the sum of their ages is 54 years find the age of the son?
The father is 40 and his son is 14, a difference of 26 years and their combined ages equal 54.
A boy is 24 years younger than his father. in 2 years time the sum of there ages will be 40 find the present ages of the father and son?
Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.
John is twice as old as his brother Four years ago he was four times as old as his brother Find their present ages?
The ages are 8 and 4
Fathers age is three years more than 3 times of son's age after three years fathers age will be 10 years morethan the twice of son's age What are their present ages?
son is 10, father is 33
A fathers age is 30 times older than his son however after 18 years he will only be thrice as old as sonfind the present age of fathers?
a father is 30 years older than his son.in 12 years,the men will be three times as old as his son.find their present ages.
If the father's age in 3 years will be twice the son's age 4 years ago and if the sum of their ages now is 106 how old is the father now?
He is 67.
The sum of the ages of a mother a father and their son is 100 years Each of their ages is a multiple of 10 and the mother was thirty years old when her son was born How old is the son?
10
A father is twelve times as old as his son and the difference in their ages is 40 years. How old is each?
son- b/t 3 and 4 dad- b/t 36 and 48
Why was this time period given the name the middle ages?
It was given the name middle ages because it was the years between prehistoric times and modern times.
The difference between the ages of two friends is 37 years The sum of their ages is 55 years Find the age of the older friend?
46
Maya's brother was 12 when she was born The sum of their ages is 22 find their ages?
17.5 years For Maya's brother and Maya is 5.5 years of age.
If a son is one half of his father's his age is 72 what is the sum of there ages?
108 years Father = 72 Son = 36 (1/2 of father's) 72 + 36 = 108
