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An integer is chosen at random from the first 50 digitswhat is the probability that it is divisible by 6 or 8?
Wiki User
∙ 14y ago
There are 8 integers under 50 divisible by 6 and 6 divisible by 8. 24 and 48 are common multiples so there are 12 qualifying integers. Probability is therefore 12 out of 50 or 24%.
(6,8,12,16,18,24,30,32,36,40,42,48.)
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∙ 14y ago
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What is the probability that a number chosen is divisible by 2?
50 50 odd or even same probability
Suppose a 10 digit positive integer leading digit not zero is chosen at random What is the probability that the digits in this integer are NOT distinct?
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As all the angles in a square measure 90°, the probability of 2 randomly chosen angles being congruent is 1.
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What is the probability that a number chosen is divisible by 2?
50 50 odd or even same probability
A number is chosen at random from the first twelve whole numbers. What is theThe probability that it is isExactly divisible by 3?
1/3
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The answer is 9*9!/9*109 = 0.0003629 approx.
How do you find the probability of a random point being chosen in a shaded region in a circle?
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What is the probability that 2 randomly chosen binomials with integer coefficients share no common factors?
They will certainly share the factor 1. Other than that, the probability is 1: it is nearly a certainty that that they will not share another common factor..
What is the probability that a randomly chosen number is not divisible by 2 3 or 6?
AnswerThe probability that a randomly chosen [counting] number is not divisible by 2 is (1-1/2) or 0.5. One out of two numbers is divisible by two, so 1-1/2 are not divisible by two.The probability that a randomly chosen [counting] number is not divisible by 3 is (1-1/3) = 2/3.Similarly, the probability that a randomly chosen [counting] number is not divisible by N is (1-1/N).The probability that a random number is not divisible by any of 2, 3 or 6 can be reduced to whether it is divisible by 2 or 3 (since any number divisible by 6 can definitely be divided by both and so it is irrelevant). This probability depends on the range of numbers available. For example, if the range is all whole numbers from 0 to 10 inclusive, the probability is 3/11, because only the integers 1, 5, and 7 in this range are not divisible by 2, 3, or 6. If the range is shortened, say just from 0 to 1, the probability is 1/2.Usually questions of this sort invite you to contemplate what happens as the sampling range gets bigger and bigger. For a very large range (consisting of all integers between two values), about half the numbers are divisible by two and half are not. Of those that are not, only about one third are divisible by 3; the other two-thirds are not. That leaves 2/3 * 1/2 = 1/3 of them all. As already remarked, a number not divisible by two and not divisible by three cannot be divisible by six, so we're done: the limiting probability equals 1/3. (This argument can be made rigorous by showing that the probability differs from 1/3 by an amount that is bounded by the reciprocal of the length of the range from which you are sampling. As the length grows arbitrarily large, its reciprocal goes to zero.)This is an example of the use of the inclusion-exclusion formula, which relates the probabilities of four events A, B, (AandB), and (AorB). It goes like this:P(AorB) = P(A) + P(B) - P(AandB)In this example, A is the event "divisible by 2", and B is the event "divisible by 3".
A number is chosen at random from the first 10 whole number What is the probability that it is not exactly divisible by 3?
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What is the probability that a random selected poker hand contains exactly 3 aces given that it contains at least 2 aces?
I will assume that you mean a five card poker hand. We can label the cards C1, C2, C3, C4, and C5. We are basically told already that C1 and C2 are both aces. So we have to find the probability that exactly one of C3, C4, and C5 is an ace. Knowing that the first two cards in our hand are both aces means that there are only 50 cards left in the deck. The probability that C3 is an ace and that C4 and C5 are both not aces is (2/50)(48/49)(47/48)=0.03836734694. The same probability also applies to each of C4 and C5, considered independently of each other. Therefore, our final probability is 3* 0.03836734694=0.1151020408
If there are 45 students in a biology class and 23 are girls what is the probability that a student chosen at random will be a boy?
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
Out of 28295 people 21786 are male what is the probability they will be chosen?
The answer depends on how many are chosen at a time.
What is the probability that 4 and 7 randomly chosen numbers in a row are all divisible by 7?
4 numbers: 1/74 = 0.000 061 035 7 numbers: 1/77 = 0.000 001 214
What is the Probability that if a number is chosen the number is even?
50%
