What the answer
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%
The answer depends onthe alphabet that you chose,whether or not you consider y to be a vowel,whether or not each letter is equally likely to be chosen (eg not from a bag of scrabble tiles), andwhether or not the choice was random.If a choice was random, from equal numbers of letters from the modern Roman alphabet and y is not considered a vowel then the answer is 5/26.
1/6 if the letter is chosen at random.
The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.
Q. A letter is chosen at random from the word STATistician.What is the probability that it is a vowel?What is the probability that it is T.
5/24, or five out of twenty four, or with numbers, five out of infinity
if you only consider the vowels to be aeiou, then the answer is that you have a 5 out of 26 (or .19%) chance.
sample space=13 no of possible outcomes (vowel)=5/13 no of possible outcomes (consonant)=7/13
What the answer
There are 10 letters in the word "aspiration" and 5 of them are vowels. The probability of a randomly-selected letter being a vowel are 5/10 = 1/2 = 0.50.
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%
4 because in word perseverance we have 4 letters E
The answer depends onthe alphabet that you chose,whether or not you consider y to be a vowel,whether or not each letter is equally likely to be chosen (eg not from a bag of scrabble tiles), andwhether or not the choice was random.If a choice was random, from equal numbers of letters from the modern Roman alphabet and y is not considered a vowel then the answer is 5/26.
1/6 if the letter is chosen at random.
The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.
The word 'probability' has 11 letters and 5 of them are vowels (including the 'y'). Therefore the probability of picking a vowel is 5/11.