the first 10 whole numbers are numbers 1 to 10 and in those numbers only 3 numbers are divisible by 3 in which 3, 6 and 9 therefore the probability of from those figures that the numbers won't be divisible by 3 is 7/10 or 70%.
Number of choices = 12Number of successes = 4Probability of success = 4/12 = 1/3rd = [ 33 and 1/3rd] percent
50%
NO, can 2 be divided by 6........ yes, can 4 be divided by 6......... Every number is divisible by every other number, but not always exactly. Not every number that is exactly divisible by 2 is exactly divisble by 4. Examples: 2, 18, 30, 46
339 + 1 = 340,which is exactly divisible.
12
50 50 odd or even same probability
Number of choices = 12Number of successes = 4Probability of success = 4/12 = 1/3rd = [ 33 and 1/3rd] percent
1/3
50%
AnswerThe probability that a randomly chosen [counting] number is not divisible by 2 is (1-1/2) or 0.5. One out of two numbers is divisible by two, so 1-1/2 are not divisible by two.The probability that a randomly chosen [counting] number is not divisible by 3 is (1-1/3) = 2/3.Similarly, the probability that a randomly chosen [counting] number is not divisible by N is (1-1/N).The probability that a random number is not divisible by any of 2, 3 or 6 can be reduced to whether it is divisible by 2 or 3 (since any number divisible by 6 can definitely be divided by both and so it is irrelevant). This probability depends on the range of numbers available. For example, if the range is all whole numbers from 0 to 10 inclusive, the probability is 3/11, because only the integers 1, 5, and 7 in this range are not divisible by 2, 3, or 6. If the range is shortened, say just from 0 to 1, the probability is 1/2.Usually questions of this sort invite you to contemplate what happens as the sampling range gets bigger and bigger. For a very large range (consisting of all integers between two values), about half the numbers are divisible by two and half are not. Of those that are not, only about one third are divisible by 3; the other two-thirds are not. That leaves 2/3 * 1/2 = 1/3 of them all. As already remarked, a number not divisible by two and not divisible by three cannot be divisible by six, so we're done: the limiting probability equals 1/3. (This argument can be made rigorous by showing that the probability differs from 1/3 by an amount that is bounded by the reciprocal of the length of the range from which you are sampling. As the length grows arbitrarily large, its reciprocal goes to zero.)This is an example of the use of the inclusion-exclusion formula, which relates the probabilities of four events A, B, (AandB), and (AorB). It goes like this:P(AorB) = P(A) + P(B) - P(AandB)In this example, A is the event "divisible by 2", and B is the event "divisible by 3".
40 is nearest to 39 and is exactly by divisible 4
The probability is 67/200.
NO, can 2 be divided by 6........ yes, can 4 be divided by 6......... Every number is divisible by every other number, but not always exactly. Not every number that is exactly divisible by 2 is exactly divisble by 4. Examples: 2, 18, 30, 46
To find the probability of selecting a number from 20 to 30 that is divisible by 3, we first identify the numbers in that range: 21, 24, 27, and 30. There are four suitable candidates, so the probability of selecting one of them is 4 out of 11 (the total numbers from 20 to 30, inclusive). After replacing the selected number, we check which of these are divisible by 12. Among the numbers listed, only 24 is divisible by 12. Therefore, the probability of selecting a number divisible by 3 and then finding it divisible by 12 is 1 out of 11, which simplifies to approximately 0.0909 or 9.09%.
The smallest number which is exactly divisible by the numbers 8 9 and 10 is 360.
Any even number.
339 + 1 = 340,which is exactly divisible.