if hypotenuse is 4 then each side is 4 divided by sqrt 2 = 2.828 with two angles 45 degrees
The triangle height is 2 so area is 1/2 base x height =1/2 times 4 times 2 = 4
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
Area of the right isosceles triangle: 0.5*16*16 = 128 square units
The length of the hypotenuse, alone, is not sufficient to determine the area of a triangle.
do you want to know the area in a isosceles triangle or what?
Yes providing that it's an equilateral triangle or a right angle isosceles triangle.
Area of any triangle is: 0.5*base*perpendicular height
Area of isosceles triangle: 0.5*5*7 = 17.5 square cm
Yes. The two equal sides would measure 3.
Yes providing that it is an equilateral triangle or a a right angle isosceles triangle other wise it's not possible
V= area of the triangle x length
An isosceles right triangle is a 90 degree triangle that the two non-hypotenuse sides are equal. http://mathworld.wolfram.com/IsoscelesRightTriangle.html Area of a triangle is 1/2 x b x h Area of an isosceles right triangle is 1/2 b2 144 cm2 = 1/2 b2 2 (144 cm2) = 2(1/2 b2) 288 cm2 =b2 16.97 cm = b So the base and height each equal 16.97 cm The hypotenuse can be solved by the Pythagorean Theorem a2 + b2 = c2 288 + 288 = c2 576 = c2 (576).5 = (c2).5 24 = c So the sides of an isosceles right triangle with the area of 144 cm2 are 16.97 cm, 16.97 cm, and 24 cm.
Using Pythagoras' theorem the other leg works out as 60 meters. 1/2*25*60 = 750 square meters