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What is the measure of the interior angles of a regular polygon if each exterior angle measures 72 degrees?
It is a 5 sided regular pentagon and each interior angle measures 108 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 72 degress?
Each interior angle is 108 degrees and its 5 angles add up to 540 degrees
The ratio of the angle measures in a triangle is 1 5 6 what is the measure of each angle?
15, 75 and 90 degrees.15, 75 and 90 degrees.
What is the measures of the interior angles of a regular polygon if each exterior angle measures 72?
The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.
What is the measures of the interior angles of a regular polygon if each exterior angle measures 72 degrees?
It is: 180-72 = 108 degrees and it is a regular 5 sided pentagon
What is the measure of an external angle for a pentagon?
If it's a regular 5 sided pentagon then each exterior angle measures 72 degrees
What is the measure of one interior angle of a regular polygon with 5 sides?
Each interior angle of a regular 5 sided pentagon measures 108 degrees
What is the angle between 5 and 8 on a clock face?
There are two angles between 5 and 8 on a clock face. The smaller (right) angle is 90 degrees. The larger (reflex) angle is 270 degrees.
What is the messure of one interior angle of a regular pentagon?
One interior angle of a regular 5 sided pentagon measures 108 degrees.
How many sides has a regular polygoneach angle of which is measure 108degree?
If each interior angle measures 108 degrees then it will have 5 sides which is a pentagon.
What is the sum of the measures of the interior angles of a regular polygon if each exerior angle measures 72 degrees?
There are 5 interior angles and each one measures 108 degrees (180-72). Since the sum of exterior angles of any polygon is 360⁰, then that polygon would have 5 angles (360/72). So the sum of interior angle measures is 540⁰.
In the right triangle the ration of the measures of the two acute angles is 4 to 1 what is the measure in degrees of the larger acute angle?
Since they add up to 90, the smaller angle is 90(1/5) =18 degrees, and the larger angle is 90(4/5)=72 degrees.
