As long as it end in 5 or Zero
Your question's meaning eludes me. You can divide any number by 5, whether or not it is a remainder, and why would you want to divide a remainder by 5 anyway?
Yes. Use a calculator.
to divide a number by any fraction you can multiply by the reciprocal ex) 5/(1/2)=5*(2/1)=5*2=10
We note that '125' ends in '5'. So it will divide by '5', which is a prime number. Hence 5)125 5)25 5)5 = 1 Keep dividing by any prime number, that will go into the answer, in this case '5'. So 5 x 5 x 5 = 5^(3) = 125 NB Any number that ends in '5' or '0' will divide by '5'. Any number that ends with an EVEN number will divide by '2'. Any number were the digits sum to '9' will divide by '9'. e.g. 27 ; 2 + 7 = 9 27/9 = 3
Any number that ends in 5 will have 5 as a factor, so divide. 225/5 = 45 ... divide by 5 again. 45 / 5 = 9... divide by 3 9/3 = 3 The prime factorization is 3x3x5x5.
Any number of the form 5n+4 where n is an integer.
In the decimal numbering system, if the number ends in 0 or 5 it is evenly divisible by 5. If it ends in any other number it is not.
YES!!! Any number however large, if the last (right hand) number ends in zero(0) or five(5) is divisible by '5'. e.g. 12345 will divide by '5' 12340 will also divide by '5'.
Divide the number by 100 to get 1%, then times the answer by 5 to get 5%Or, you can divide the number by 20, which will also give you 5%
You can divide any number by any other number - you just might not get an even number as the answer.
150
'2' Because any number ending in '5' or '0' will divide by '5'. Since 4912 is '2' more than 4910, which will divide by '5' , leaves a remainder of '2'.