If April swam 50 M North then swam 20 M South back then her velocity would be 16.66. This is a math problem.
Ed biked home from school in 400 seconds. His home is located 2000 m south of the school. What was his velocity
If the person sat on the train their velocity relative to the ground would be 95kph. But he/she is goind 3kph to oppose this. So 95-3 = 92 kph to the north is velocity of person relative to the ground.
Average speed = Total Distance/Total Time = (15+25)/2 = 40/2 = 20 miles per hour. Velocity (due North) = Total NET distance North/Total Time = (15-25)/2 = -10/2 = -5 miles per hour or, velocity due South = 5 miles per hour.
The overall velocity would increase. The ball would then have a curved path with some velocity vector in the North South direction and some vector in the East West Direction
yes
The resultant velocity of a plane is 75 km/hr.
.5 north
Displacement: 8 m south Time: 4 seconds Therefore velocity = 2 metres per second Southwards.
He walked 600m in 600 seconds so his velocity is 1m/s (one metre per second)
1.5 m.s north thanks to m.e.h :D
During April, the sun is moving from south to north, heading north.
20 m/s north
20 m/s north
The person travels a total of 4000 m in 400 seconds, so their average speed is 10m/s. However velocity is a vector quantity, and is defined as displacement/time. The total displacement is only 400 m, so the average velocity is just 1m/s.
5 m/s south
No. Velocity is described as a speed in a certain direction. Since they are in different directions, they are different velocities.
What I mean is can you have a negative velocity followed by "south". (i.e. -7.5 m/s south) or would the velocity be 7.5 m/s south? My opinion is that the negative sign is not necessary since south is already "negative" so you would be canceling out the negative if you have the sign making it 7.5 m/s north.