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Are 3x-4y equals -5 and 8x plus 6y equals -5 parallel or perpendicular lines?
Wiki User
∙ 12y ago
They are perpendicular lines because the slopes are 3/4 and -4/3 respectively.
Wiki User
∙ 12y ago
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What is the maximum value of 3x4y in feasible region?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. There is no visible operator between 3x4y unless some of them are meant to be powers. Also, it is necessary to know the feasible region. But since you have not bothered to provide that information, I cannot provide a sensible answer.
Is -3x4y 7 linear?
-3x*4y=7 would be linear. That equation can be turned into a slope-intercept form if simplified without any exponents nor absolute values.
What is the maximum value of 3x4y in feasible region?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. There is no visible operator between 3x4y unless some of them are meant to be powers. Also, it is necessary to know the feasible region. But since you have not bothered to provide that information, I cannot provide a sensible answer.
Is -3x4y 7 linear?
-3x*4y=7 would be linear. That equation can be turned into a slope-intercept form if simplified without any exponents nor absolute values.
How do you graph 3x plus 4y equals 5?
3x + 4y = 5To find the x-intercept, let x = 03(0) + 4y = 54y = 5y = 5/4The line passes through (0, 5/4), so y-intercept is 5/4.To find x-intercept, let y = 03x + 4(0) = 53x = 5x = 5/3The line passes through (5/3, 0), so x-intercept is 5/3.Plot (0, 5/4) and (5/3, 0). Draw a straight line through them.Or,3x + 4y = 53x - 3x + 4y = 5 - 3x4y = -3x + 54y/4 = (-3x + 5)/4y = (-3/4)x + 5/4So the slope will be -3/4 and the y-intercept is 5/4; (0, 5/4)We find the x-intercept when y = 0, so0 = (-3/4)x + 5/40 - 5/4 = (-3/4)x + 5/4 - 5/4-5/4 = (-3/4)x(-5/4)/(-3/4) = [(-3/4)x]/(-3/4)5/3 = x ; (5/3, 0)Thus, the line passes through the points (0, 5/4) and (5/3, 0).
