No because they are both rational numbers
Not necessarily. The cube roots of 4, 6 and 9 are all irrational (and different). But their product is 6, not just rational, but an integer.
it is irrational because it's from the exponential numbers
No -6 can be expressed as a fraction (-6/1) and therefore cannot be irrational. Irrational numbers cannot be expressed as fractions.
No they are not. The numbers Pi and e are irrational and are not radicals. There are many others.
no it is not irrational irrational is a neverending number like2.36945856235......... that goes on and on 6 over 7 is a rational number rational numbers are whole numbers natural numbers and integers.
There are infinite irrational numbers between 1 and 6.
Irrational numbers are infinitely dense. Between any two numbers, there are infinitely many irrational numbers. So if it was claimed that some irrational, x, was the closest irrational to 6, it is possible to find an infinite number of irrationals between 6 and x. Each one of these infinite number of irrationals would be closer to 6 than x. So the search for the nearest irrational must fail.
The irrational number closest to 6 is the square root of 36, which equals 6. This is because the square root of 36 is a rational number that is the closest approximation to 6 among irrational numbers. The square root of 36 is equal to 6, making it the irrational number closest to 6.
rational numbers can be represented as a ratio of integers such as 1/4 and irrational numbers can NOT. Square root of 2 is an irrational number.
No, it is not irrational because it is a square root of a negative number - which falls into the set of Complex numbers. Irrational numbers can not have an imaginary component.
Not necessarily. 3+sqrt(2) and 3-sqrt(2) are both irrational numbers. Their sum is 6 - a rational.
No.