No, it is not irrational because it is a square root of a negative number - which falls into the set of Complex numbers. Irrational Numbers can not have an imaginary component.
Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of 2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4).
It is irrational. * The square root of any positive integer, except of a perfect square, is irrational. * The product of an irrational number and a rational number (except zero) is irrational.
No; you can prove the square root of any positive number that's not a perfect square is irrational, using a similar method to showing the square root of 2 is irrational.
the square root of 3, the square root of 5, the square root of 6, the square root of 7, the square root of 8 etc
It is an irrational number and works out as 14 times the square root of 6 or about 34.2928564
Yes.
It is known that the square root of an integer is either an integer or irrational. If we square root2 root3 we get 6. The square root of 6 is irrational. Therefore, root2 root3 is irrational.
No. The square root of 6 is irrational.
6 times the square root of 6
It is an irrational number.
irrational
Yes. For example, the square root of 3 (an irrational number) times the square root of 2(an irrational number) gets you the square root of 6(an irrational number)
Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of 2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4).
No. For two reasons: 1) Negative numbers are not natural numbers 2) All natural numbers are rational numbers but the square root of 6 is an irrational number and thus cannot be a natural number.
The square root of 6 is an irrational number; it can only be approximated as a decimal. √6 ≈ 2.449
yes.
It is irrational. * The square root of any positive integer, except of a perfect square, is irrational. * The product of an irrational number and a rational number (except zero) is irrational.