No, it is not irrational because it is a square root of a negative number - which falls into the set of Complex numbers. Irrational Numbers can not have an imaginary component.
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Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of 2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4).
It is irrational. * The square root of any positive integer, except of a perfect square, is irrational. * The product of an irrational number and a rational number (except zero) is irrational.
No; you can prove the square root of any positive number that's not a perfect square is irrational, using a similar method to showing the square root of 2 is irrational.
the square root of 3, the square root of 5, the square root of 6, the square root of 7, the square root of 8 etc
No because the square root of 36 is 6 which is a rational number