No. Consecutive means that they are next to each other (i.e. the larger minus the smaller equals 1). Such as 2 and 3.
The 10 digits are: 0,1,2,3,4,5,6,7,8,9
As you can see 0 and 9 are not next to each other, so they are not consecutive.
Digits or decimal digits more specifically. The decimal system has 10 unique digits 0-9.
9
There is nothing "in" digits. Digits are single characters representing the ten integers from 0 to 9 (inclusive).
The digits from 0 to 9, and the decimal point (or comma, depending on the country).The digits from 0 to 9, and the decimal point (or comma, depending on the country).The digits from 0 to 9, and the decimal point (or comma, depending on the country).The digits from 0 to 9, and the decimal point (or comma, depending on the country).
How many permutations of 3 different digits are there, chosen from the ten digits 0 to 9 inclusive?
Perhapsf you specified the number of digits. e.g. 0-9 with two digits.
The answer is 10P3 = 10!/(10-3)! = 10*9*8 = 720
1000
There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.
Digits
Of the ten digits, 0 is the only one that is divisible by 9.
That is 8001. For a number is divisible by 9, the digits must sum up to 9 (or a multiple of 9). So for 8000, the digits sum to 8 [8 + 0 + 0 + 0 = 8]. So you're only 1 away from 9 [8 + 0 + 0 + 1 = 9]