Yes. Even numbers can be divisible by two.
Yes because all numbers that end in zero are divisible by ten
All numbers are divisible by ten but if you are referring to numbers that are divisible by ten and produce a whole number, you are referring to multiples of 10 or any number ending in 0.
no, some examples are 15, 25, 35 etc However, all numbers divisible by ten are divisible by five
because they just do
No - numbers are only divisible exactly by ten - if they end in a zero !
No one-digit numbers are divisible by 10. 10 is divisible by 1, 2 and 5.
Any whole number whose last digit is a zero will be divisible by ten; the result is easily found by simply removing the zero in question.
None of the numbers in that range are divisible by 495. 495 is divisible by 3 and 5.
Every number with a 0 at the end of it
No. For one thing, 25 is an odd number (ends in 5). 10 is even, meaning is it divisible by 2. All even numbers are divisible by 2; all numbers divisible by 2 are even. 25 isn't one of them. So it is not a multiple of 10. For another, just try multiplying 10, the way you would count dimes or ten-dollar bills: 10, 20, 30...did you mention 25? 25 is two and a half tens.
what is divisible by two,three,four,five and ten
There are ten.
All the numbers divisible by 5 are the numbers ending with the digit 5 or 0. The first ten examples are: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50
Any number which ends in a 0 will be divisible by ten (except for 0 itself). For example; 10, 20, 30, 450, 1480, 4355942220 and 100 are all divisible by 10.
There is only one even prime number. It is the number two. All other even numbers are composite.
48 is divisible by ten factors. There is an infinite amount of numbers divisible by 48.
2 , 4 and 7 if you are listing through ten
80%. Out of every ten numbers, one is divisible by 10, and that same one plus one moreare both divisible by 5. The remaining eight are divisible by neither 5 nor 10.
10, 20, 30, 40, and so on. In other words, any multiple of ten (and only multiples of ten) are divisible by both 2 and 5.
Because 10 is divisible by 2 with no remainder
30, 60, 90, 120, 150, and all other multiples of 30 are divisible by 6 and 10