None of the numbers in that range are divisible by 495. 495 is divisible by 3 and 5.
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The foolproof way is to divide 4 into it. If the answer is a whole number, it's divisible by 4. You can also tell by looking at it. If the last two digits are a multiple of 4, like 24 or 80, the whole number is divisible by 4.
There is no number, no matter the number of digits, that is only divisible by 2.
Yes, 928 is divisible by two because it is an even number. A number is divisible by two if it can be divided evenly by 2 without leaving a remainder. In this case, 928 divided by 2 equals 464, which is a whole number without any remainder, confirming that 928 is indeed divisible by two.
With the exception of zero, anything is divisible by anything. We're more concerned with the result. Dividing a smaller number by a larger number will result in a fraction. 2/180 or 1/90 = 0.0111 repeating
How can the following definition be written correctly as a biconditional statement? An odd integer is an integer that is not divisible by two. (A+ answer) An integer is odd if and only if it is not divisible by two