The statement "A system of linear equations is a set of two or more equations with the same variables and the graph of each equation is a line" is true.
A system of linear equations is two or more simultaneous linear equations. In mathematics, a system of linear equations (or linear system) is a collection of linear equations involving the same set of variables.
They are not. An inequality cannot, by definition, be the same as an equation.
The equations are equivalent.
A system of linear equations that has one unknown is a set of equations that all depend on the same variable. An example is y = 1 + 3x and y = 4 + 7x.
A system of linear equations.
a system of equations
If the two equations are linear transformations of one another they have the same solution.
Two dependent linear equations are effectively the same equation - with their coefficients scaled up or down.
Equations with the same solution are called dependent equations, which are equations that represent the same line; therefore every point on the line of a dependent equation represents a solution. Since there is an infinite number of points on a line, there is an infinite number of simultaneous solutions. For example, 2x + y = 8 4x + 2y = 16 These equations are dependent. Since they represent the same line, all points that satisfy either of the equations are solutions of the system. A system of linear equations is consistent if there is only one solution for the system. A system of linear equations is inconsistent if it does not have any solutions.
Quite simply, the latter is a group of the former.A system of linear equations is several linear equations taken together, each using the same group of unknowns. Usually, such a system provides one linear equation for each unknown (x, y, z, et al) that must be found (more complex systems can exist, though). You can use and manipulate these linear equations as you would a single linear equation to help solve for the unknowns. One way is to reduce all but one of the unknowns so that each can be expressed in terms of the remaining unknown and then solve for the remaining unknown which would in turn give you the others.