3 and 9
-3
No. It is a prime number and is only divisible by 1 and itself.
Every one of the infinite number of multiples of 9 is, as well as roughly 1/3 of the multiples of 3. There sure are a huge number of them.
2, 3, 6, yes. 4, 5, 9, 10, no.
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
35 is not divisible by 3.
If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
There is no such number. Since 6 is divisible by 3, then any number that is divisible by 6 automatically has to be divisible by 3.
A number is divisible by 3 if the sum of its digits is divisible by 3.
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
3