A + B = - 3 ===> B = - 3 - A
A B = - 12 ===> A ( - 3 - A ) = -12
-3A -A2 = -12
A2 + 3A -12 = 0
A = [ -3 +/- sqrt(9 + 48) ] / 2
This is far enough to answer the question. The two solutions for 'A' both involve the square root of 57, which is 7.5+ . So neither solution for 'A' can be an integer. And, since 'B' is 3 less than -A, 'B' can't be an integer either. The answer to the question is No.
The integers 2 and 10 have a product of 20 and a sum of 12.
Two integers that have a sum of -7 and a product of 12 are -3 and -4.
12 and -2
Factor 12 = 2x2x3 There's no combination for -12 as a product and -3 as a sum at the same time.
-3 and -4
12
The product of the two integers is -80.
11 & 14
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
The integers are -7 and -5.
1 2 and 3
-15 and 5.