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Q: If the largest of three consecutive even integers is multiplied by three the product is 2 less than twice the sum of the first two integers find the integers?

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There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.

There is no set of two consecutive integers equating to 200.

what is the formula to use to solve the product of two consecutive odd integers

The two consecutive odd integers having a product of 99 are 9 and 11.

I think you mean consecutive even integers: 20 & 22

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-7 multiplied by -8 = 56

9240 is the product of the three consecutive integers 20, 21, and 22.

There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.

Consecutive odd integers would be 5 and 7.

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There is no set of two consecutive integers having a product of 14. Product means the result of multiplication.

There are no two consecutive integers whose product is 421 - the product of 20 and 21 is 420.

The product of two consecutive integers is 132. Find the two integers. They are: 11*12 = 132

-9 or -10Two consecutive negative integers that can be multiplied together with a product of 90 would be -9 and -10. A number sentence for this equation would be: -9 X -10 = 90.

No, it is not. It is the sum of two consecutive integers: 46 and 47.

There is no set of two consecutive integers equating to 200.

Their product is 143.

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