With perimeter 10 and all sides equal fora rhombus, each side (base) is 10/4 = 2.5 inch Area = base times altitude = 2.5 x 12 = 30
The answer depends on what information is given to you.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
From the given information and by using trigonometry the perimeter in cm of the rhombus works out as 15 times the square root of 2
There is no relationship between the perimeter and the area of a rhombus. Take a rhombus with all 4 sides = 2 units. Therefore the perimeter is 8 units. There are an infinite number of possible areas for this rhombus. The largest possible area will be when the rhombus approaches the shape of a square = 4 square units. The smallest area will be when the one diagonal approaches 0 units and the other diagonal approaches 4 units (squashed almost flat). So two very extreme areas can have the same perimeter, including all those areas in-between.
Its perimeter is the sum of its 4 sides Its area is 0.5 times the product of its diagonals
Base 1= 5 Perimeter 1=20 altitude 1= 4 A/P1 = 4*24/20 = 24/5 = 4.8 Base 2=3 Perimeter 2=12 altitude 2= 4*24/12 = 4*2 =8
Area equals base times height. The perimeter is 4 times the length of one side.
The perimeter and area of a shape do not provide sufficient information. With a given perimeter, the largest area that you can enclose is a circle, but you can then flatten the circle to reduce its area. Similarly, in terms a of quadrilaterals, a square has the largest area, but it can be flexed into a rhombus whose area can be made as small as you like. All that can be said is that there is no shape with a perimeter of 12 units whose area is 12 square units.
Units, because the perimeter is just the edge. The area is square units.
Begs the question: Same perimeter as what? There are plenty of examples of shapes that given the same perimeter length will have different areas, e.g. pick any two of the following: Circle, Square, Triangle, Rhombus, Pentagon, Hexagon...
P = 4*a (a is side length) Area = p*q/2 (p=perimeter, q=diagonal
Given any shape with a given area you can another shape with the same area but a different perimeter. And convesely, given any perimeter you can have another shape with the same perimeter but a different area. And these apply for the infinite number of shapes.
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm? . Area = base * height Altitude = height. Altitude = 4 cm . A rhombus has all 4 sides equal, so the base = 6 cm . Area = base * height . Area = ____sq. cm.
In general you cannot find the perimeter of any shape if only the area is given.
If you are given the width and the perimeter, then figure out what the length is then calculate the area... hope this helps :)
130 is the area.
Perimeter = 4 times the square root of the area.
There is insufficient information to answer the question. For a given area, the perimeter depends upon the shape. For a given area, the circle will have the smallest perimeter. For polygons, regular polygons will have a smaller perimeter than an irregular one of the same area. Also, for regular polygons, the greater the number of sides, the smaller the perimeter.
Not enough information given
The perimeter is 44 units.
The answer is given below.