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Q: Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm?

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Area of the rhombus: 0.5*8*10 = 40 square feet

Area = 0.5*12*8 = 48 square units

It is: 0.5*10*12 = 60 square m

Find the area of a rhombs with diagonals that measure 8 and 10.

54

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130 is the area.

Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter

A = baWhere A = areab = length of the basea = altitude (height).

123

28

30

150 sq meters

Area of the rhombus: 0.5*8*10 = 40 square feet

Area of a rhombus = 0.5 times the product of its diagonals

That is one of the ways of finding the area of a rhombus. The area is half the product of the diagonals. In this case, 1/2 of 7 x 4.4 or .154. You can also find the area of a rhombus by using one side as the base and finding an altitude for that base and multiplying them. There is a third way using trigonometry.

With perimeter 10 and all sides equal fora rhombus, each side (base) is 10/4 = 2.5 inch Area = base times altitude = 2.5 x 12 = 30

Area = 0.5*12*8 = 48 square units

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