it is impossible for a diagonal of a rhombus to be the same length as its perimeter
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P = 4*a (a is side length) Area = p*q/2 (p=perimeter, q=diagonal
There is no relationship between the perimeter and the area of a rhombus. Take a rhombus with all 4 sides = 2 units. Therefore the perimeter is 8 units. There are an infinite number of possible areas for this rhombus. The largest possible area will be when the rhombus approaches the shape of a square = 4 square units. The smallest area will be when the one diagonal approaches 0 units and the other diagonal approaches 4 units (squashed almost flat). So two very extreme areas can have the same perimeter, including all those areas in-between.
Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
63
Diags of rhombus form 4 Pythagorean triangles. If these triangles sides are 10 and 8 cm then hypotenuses would be 12.8 cm. Each hypotenuse is one side of the rhombus so perimeter would be 51.2 cm to nearest mm.