It reflects at like 45 degrees I think. No, it reflects off at the same angle it hits the mirror. If the light wave hits the mirror at a 30o angle on the left side, it will reflect off at a 30o angle on the right side. Scientists usually measure these angles from an imaginary line perpendicular to the mirror at the point where the light wave hits the reflecting surface; sounds awkward, but it makes the math easier.
light is needed to reflect an image off a mirror...no light no reflection
A line of reflection is a reflected line, often off of a mirror. If a flashlight sends a beam of light at a mirror (the light is called the incident beam), the angle at which it hits the mirror will equall the angle at which the reflected beam of light (called the reflected beam), exits the mirror. This is called the Law of Reflection. This is why light is reflected from a mirror at the same angle at which light struck its surface. A line of reflection is a reflected line, often off of a mirror. If a flashlight sends a beam of light at a mirror (the light is called the incident beam), the angle at which it hits the mirror will equall the angle at which the reflected beam of light (called the reflected beam), exits the mirror. This is called the Law of Reflection. This is why light is reflected from a mirror at the same angle at which light struck its surface.
A parallel light source will reflect off a concave mirror and go through a point inside the curve called the focus. Reflecting from a convex mirror will cause all light to bounce off in a straight line away from a focus point behind the mirror.
the same angle with which it (the incident ray) hits the mirror surface. this physical law is known by the formula α =β.there´s a simple way to prove it: look into a (palin) mirror and ask someone else to look into the same mirror - preferrably from another distance. as long as you can see their reflection they should be able yo see yours and vice versa.
Yes, the beam just reflects off of the mirror. There is no beam created from the mirror.
it will reflect off it
light is needed to reflect an image off a mirror...no light no reflection
They would bounce off the mirror and become nonparallel going off at whatever angle they hit the mirror at, in different directions.
Depending on which angle the light hits, it will reflect off the mirror and go somewhere else.
the angle of reflection is the angle where light bounces off the object. for example if you have a mirror the angle of reflection is the one that you can point a laser at the mirror and bounces off.
amsw2. A mirror, provided it is smooth to below the wavelength of light, will reflect the light in the same way you can see a water wave be reflected from a wall.
The angle between the incident ray and the mirror is equal to the angle between the reflected ray and the mirror.
The incident angle to the Mirror will be 10 deG.
amsw2. A mirror, provided it is smooth to below the wavelength of light, will reflect the light in the same way you can see a water wave be reflected from a wall.
yes it can because reflection is logic
The bumpy mirror will reflect the light at a weird angle, not the one you would expect, based on where the light source is coming from. The smooth mirror will act normal
A line of reflection is a reflected line, often off of a mirror. If a flashlight sends a beam of light at a mirror (the light is called the incident beam), the angle at which it hits the mirror will equall the angle at which the reflected beam of light (called the reflected beam), exits the mirror. This is called the Law of Reflection. This is why light is reflected from a mirror at the same angle at which light struck its surface. A line of reflection is a reflected line, often off of a mirror. If a flashlight sends a beam of light at a mirror (the light is called the incident beam), the angle at which it hits the mirror will equall the angle at which the reflected beam of light (called the reflected beam), exits the mirror. This is called the Law of Reflection. This is why light is reflected from a mirror at the same angle at which light struck its surface.