The half maximum range of a projectile is launched at an angle of 15 degree
yes it does. you see if you have it set up at a a 90 degree angle it will go further than it would of a 10 degree angle A projectile leaving the ground at an angle of 45 degrees will attain the maximum range. Fire it straight up and it will fall back to its launch location (wind effects etc. ignored). Fire it horizontally and it will hit the ground very much the same time as if it was dropped from its launch platform at the same time. That would not be very far.
Yes. They will both initially be moving at the same speed.
look up naked penus Wow. Some people have nothing to do but waste time. There is no way to answer that as asked A very general answer is, whatever angle will cause the projectile to land where you want it to.
A shot is a projectile. That is, a massive body that is launched with an input of force but which, unlike a rocket, has no further energy input. In mechanics, its trajectory is usually calculated on the assumption that the only force acting on the projectile, after its launch, is the force of gravity. That is, aerodynamics do not play a part.
1. You need to know the velocity of the projectile (V0) 2. The expressions for the range and height assume no air resistance (in vacuum) 3. The units must be consistent e.g. metres and g = 9.81 m/s2 Range in metres for 30 degree launch angle = sin 60 x V02 / 9.81 Range in metres for 45 degree launch angle = sin 90 x V02 / 9.81 Range in metres for 60 degree launch angle = sin 120 x V02 / 9.81 Max. height in metres for 30 degree launch angle = (V0 x sin 30)2 / 2g Max. height in metres for 45 degree launch angle = (V0 x sin 45)2 / 2g Max. height in metres for 60 degree launch angle = (V0 x sin 60)2 / 2g 2g is of course 9.81 x 2 = 19.62 m/s2 For interest, at 45 degree launch angle the max. height is 25% of the range.
It is a case of Trigonometry/Geometry. The two triangles formed by the angles and sides of artillery aiming are "Similar" (not congruent) since two angles and a side (base) are Similar. Because the Range of the projectile is 2x the base (which is congruent) of the triangles, the range MUST be the same.
We would object to that statement, and argue that the motion of a projectile after launch is determined by the speed and direction of the launch.
leverage
The vertical component of the projectile's motion is uniformly accelerated, no matter what the angle of launch was.
If it uses gunpowder to launch a projectile it is considered a firearm
Some of the factors that determine the movements of a projectile include: air resistance, force of gravity, initial launch velocity, the angle a projectile was launched at, and the objects initial elevation.
yes it does. you see if you have it set up at a a 90 degree angle it will go further than it would of a 10 degree angle A projectile leaving the ground at an angle of 45 degrees will attain the maximum range. Fire it straight up and it will fall back to its launch location (wind effects etc. ignored). Fire it horizontally and it will hit the ground very much the same time as if it was dropped from its launch platform at the same time. That would not be very far.
Yes. An example would be a ranged weapon. This is any weapon that can launch a projectile.
Yes. They will both initially be moving at the same speed.
east
look up naked penus Wow. Some people have nothing to do but waste time. There is no way to answer that as asked A very general answer is, whatever angle will cause the projectile to land where you want it to.
It launches because the cup flies rapidly forward when the arm is released. Whatever is in the cup will then take flight.