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Is initial velocity y the same for an angled launch and a horizontal launch if you use the same projectile launcher?
Wiki User
∙ 12y ago
Yes. They will both initially be moving at the same speed.
Wiki User
∙ 12y ago
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How do you find vertical and horizontal components when given the initial velocity?
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).
How to find the height of the projectile launch if the angle velocity and the distance are given?
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
Given the velocity of a projectile the angle of projection and the mass of the object how do you determine the distance traveled?
Given the initial velocity V, and the angle from the ground A, the total distance travelled X will be: X = 2 V2 cos(A) sin(A) / gwhere "g" is the acceleration due to gravity, on earth g is approximately 9.81 m/s2.You will notice that the mass of the object does not affect the distance traveled. We can derive this by first determining how long the projectile will be in the air. If the initial velocity is V, then the initial vertical velocity is Vsin(A). The vertical velocity will decrease at a rate of 'g' until the vertical velocity reaches zero (known as apogee), and the projectile starts falling down. The time from launch to apogee will be Vsin(A)/g.The time for the projectile to go up is the same as for the projectile to fall down again, so the total time in the airis 2Vsin(A)/g.Assuming we neglect friction, the horizontal velocity is Vcos(A) and does not change. The total distance traveled horizontally is the horizontal speed multiplied by the time spend in the air. So X = 2Vsin(A)/g * Vcos(A) = 2V2cos(A)sin(A)/g.The maximum distance is achived with an angle of 45o. The distance travelled is symmetric around this value, i.e. an angle of 50o will give the same distance as 40o, and an angle of 15owill give the same distance as 75o.
Can the effect of initial velocity on final velocity be predicted?
Well, (final velocity) = (initial velocity) + (acceleration x time)
A projectile is thrown with an initial velocity which has a horizontal component of 4 m s What will be its horizontal speed after 3s?
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
How does a projectille differ from an object in a free fall?
A projectile has an initial forward velocity.
What is the value of constant horizontal velocity?
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
How is the horizontal component of velocity for a projectile affected by the vertical component?
The horizontal component of velocity for a projectile is not affected by the vertical component at all. Horizontal component is measured as xcos(theta) Vertical component is measured as xsin(theta) Whereas theta is the angle, and x is the magnitude, or initial speed.
How does projectile differ from an object in free fall?
A projectile has an initial forward velocity.
How does a projectile differ from an object free fall?
A projectile has an initial forward velocity.
What is the horizontal acceleration of a projectile as its position changes?
In the usual simple treatment of projectile motion, the horizontal component of the projectile's velocity is assumed to be constant, and is equal to the magnitude of the initial (launch) velocity multiplied by the cosine of the elevation angle at the time of launch.
What do you you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What is the horizontal range of a projectile initial velocity is doubled?
If "range" means that the shooter and the target are on the same level: quadrupled (if airesistance can be neglected). It takes twice the time until gravity "eats up" vertical velocity and during that time the projectile moves with double horisontal velocity. But if you shoot horisontally from a cliff at double velocity the flighttime will be the same and the range only doubled.
Which information is needed to determine the horizontal distance a projectile travels?
-- the initial horizontal speed of the projectile -- the time it remains in flight before it hits the ground
What is the initial direction on the projectile's velocity?
its upward at some specified angle
