Same as the average of the extremes only, that is, of 13 and 37.
50
(125/4) or 31.25
You are asking for the arithmetic mean for 25 consecutive integers starting at 13. (13+14+...+36+37) / 25 = 25 But there is a trick to this question. Since (13+37)/2 = (14+36)/2 = (15+35)/2 = ... = (24+26)/2 = 25/1 = 25, you only needed to calculate (13+37)/2 =25. The same is true for any sum of consecutive integers. For more information, look up "arithmetic series".
The integers are 37 and 39.
66
All integers can be represented with a denominator of 1. Example : 25 = 25/1 ; 37 = 37/1. Further equivalent fractions can then be created : 25/1 = 50/2 = 75/3.......and so on.
They are: -18+(-19) = -37
The positive odd integers of 49 are all the odd integers that are less than or equal to 49. These integers are 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, and 49. There are a total of 25 positive odd integers up to 49.
The integers are 37, 38 and 39.
18+19 = 37
The numbers are 37 and 39.
Let the integers be x, (x+1) and (x+2) Since, x+(x+1)+(x+2) = -114, by solving the equation for x, we get that, x = -37 Hence the integers are -37, -36 and -35