Let the integers be x, (x+1) and (x+2) Since, x+(x+1)+(x+2) = -114, by solving the equation for x, we get that, x = -37 Hence the integers are -37, -36 and -35
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The integers are 37, 38 and 39.
27 + 28 + 29 + 30 = 114
118
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
There are no three consecutive odd integers who's sum equals 13.