0
What else can I help you with?
What is the sum of the three consecutive integers that equals 114?
The integers are 37, 38 and 39.
What integers are four consecutive integers whose sum is 114.?
27 + 28 + 29 + 30 = 114
4 consecutive even integers whose sum is -114?
118
What is three consecutive integers whose sum is 117?
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
The sum of three consecutive even integers is 114?
Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.
What is the sum of the three consecutive integers that equals 114?
The integers are 37, 38 and 39.
Consective even integers Find three consective integers whose sum is 114?
The consecutive odd integers for 114 are 37, 38 and 39.
Three consecutive integers have a sum of 12. What is the greatest of these integers?
Three consecutive integers have a sum of 12. What is the greatest of these integers?
What integers are four consecutive integers whose sum is 114.?
27 + 28 + 29 + 30 = 114
What is the sum of three consecutive integers of 71?
There is no set of three consecutive integers whose sum is 71.
4 consecutive even integers whose sum is -114?
118
The sum of the three consecutive integers?
The sum of three consecutive integers is -72
What are 4 consecutive integers whose sum is 114?
The integers are 27, 28, 29 and 30.
What is three consecutive integers whose sum is 117?
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
What are three consecutive odd integers whose sum is 13?
There are no three consecutive odd integers who's sum equals 13.
The sum of three consecutive even integers is 114?
Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.
What are 4 consecutive integers whose sum equals 114?
27+28+29+30=114
