$13,366.37
compounded annually--$43,219 compounded quarterly--$44,402 compounded monthly-- $44,677 compounded daily--$44,812
12100
13310
$10,000 times (1.1)3 = $13,310
$16,105.10 if compounded yearly, $16,288.95 if compounded semi-annually, $16,386.16 if compounded quarterly, $16,453.09 if compounded monthly, and $16,486.08 if compounded daily.
The amount required is 7641.49
You do not tell us how a month you would be receiving. 400 X 24 = 9600
Value = 10000*[1 + 21/(100*12)]^(20*12)= 643073.03 approx.Value = 10000*[1 + 21/(100*12)]^(20*12)= 643073.03 approx.Value = 10000*[1 + 21/(100*12)]^(20*12)= 643073.03 approx.Value = 10000*[1 + 21/(100*12)]^(20*12)= 643073.03 approx.
Deposit 4776.06 The frequency of compounding does not matter since the annual interest rate is given.
Compounded yearly, you would end up with $11,901.16
To calculate the amount John will have after two years with a principal of $10,000 invested at an annual compound interest rate of 10%, we can use the formula for compound interest: [ A = P(1 + r)^n ] where ( A ) is the amount after time ( n ), ( P ) is the principal, ( r ) is the interest rate, and ( n ) is the number of years. Plugging in the values, we get: [ A = 10000(1 + 0.10)^2 = 10000(1.10)^2 = 10000(1.21) = 12100. ] Thus, after two years, John will have $12,100.
1200