13310
12100
6% compounded annually is equivalent to an annual rate of 12.36%. To increase, at 12.36% annually for 3 years, to 10000, the initial deposit must be 7049.61
It makes a difference how often the interest is compounded, and you haven't given that information. If it's compounded annually, then your 10,000 becomes 12,762.82 after 5 years. If it's compounded quarterly, then it becomes 12,820.37 . If it's compounded "daily", then it becomes 12,840.03 . If it's "simple" (uncompounded) interest, then 10,000 swells to a full 12,500 in 5 years.
There is no such thing as "compounded continuously". No matter how short it may be, the compounding interval is a definite amount of time and no less.
1250/12.5 = 10000 Therefore, 1250 is 10000 percent of 12.5.
12100
$10,000 times (1.1)3 = $13,310
compounded annually--$43,219 compounded quarterly--$44,402 compounded monthly-- $44,677 compounded daily--$44,812
$16,105.10 if compounded yearly, $16,288.95 if compounded semi-annually, $16,386.16 if compounded quarterly, $16,453.09 if compounded monthly, and $16,486.08 if compounded daily.
6275 will be worth 10001.40 while 6274 will not be enough.
yr. 3 - 21,632 x .04 = 865.28 i total yeild at the end of year 3 is 22,497.28 or 2,497.28 over investment
6% compounded annually is equivalent to an annual rate of 12.36%. To increase, at 12.36% annually for 3 years, to 10000, the initial deposit must be 7049.61
It makes a difference how often the interest is compounded, and you haven't given that information. If it's compounded annually, then your 10,000 becomes 12,762.82 after 5 years. If it's compounded quarterly, then it becomes 12,820.37 . If it's compounded "daily", then it becomes 12,840.03 . If it's "simple" (uncompounded) interest, then 10,000 swells to a full 12,500 in 5 years.
Compounded yearly, you would end up with $11,901.16
It depends on how it is calculated, but here is a list of the common answers depending on the method of interest earning: Compounded Annually: $10,000 x .05 = $500 / 12 = ~ $41.67
1200
To calculate the amount John will have after two years with a principal of $10,000 invested at an annual compound interest rate of 10%, we can use the formula for compound interest: [ A = P(1 + r)^n ] where ( A ) is the amount after time ( n ), ( P ) is the principal, ( r ) is the interest rate, and ( n ) is the number of years. Plugging in the values, we get: [ A = 10000(1 + 0.10)^2 = 10000(1.10)^2 = 10000(1.21) = 12100. ] Thus, after two years, John will have $12,100.