Lets start by thinking of a clock as a circle, with directly up being 0 degrees. At 12:00, both hands are at 0 pointing straight up. Every 60 minutes, the minute hand will make a complete revolution, so at any given time its angle is:
minute_deg = minute * 360 / 60 = minute * 6;
The hour hand will make a complete revolution every hour, so its formula is:
hour_deg = hour * 360 / 12 = hour * 30;
A function to find the angle would be:
int angleBetweenHands(int hour, int minute)
{
if(hour > 12) // In case of 24 hour clock
hour -= 12;
int angle = hour * 30 - minute * 6;
if(angle > 180)
angle = 360 - angle;
return(angle);
}
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Each minute is six degrees.
minute_deg = minute * 360 / 60 = minute * 6;The hour hand will make a complete revolution every hour, so its formula is:hour_deg = hour * 360 / 12 = hour * 30;A function to find the angle would be:int angleBetweenHands(int hour, int minute){if(hour > 12) // In case of 24 hour clockhour -= 12;int angle = hour * 30 - minute * 6;if(angle > 180)angle = 360 - angle;return(angle);}Read more: C_code_to_find_angle_between_hour_hand_and_minute_hand
39o26' (to the nearest minute) Explanation: Let the angle = θ sinθ = 0.6352 To find the angle of sinθ, you must apply sin-1 to sinθ. sin-1θ = 39o26'5.35"
Any angle between 0 and 180 degrees or 0 and pi radians.
The angle of depression of a point is the angle between the line joining that point and the point of observation and the horizontal from the point of observation.
Each minute is six degrees.
minute_deg = minute * 360 / 60 = minute * 6;The hour hand will make a complete revolution every hour, so its formula is:hour_deg = hour * 360 / 12 = hour * 30;A function to find the angle would be:int angleBetweenHands(int hour, int minute){if(hour > 12) // In case of 24 hour clockhour -= 12;int angle = hour * 30 - minute * 6;if(angle > 180)angle = 360 - angle;return(angle);}Read more: C_code_to_find_angle_between_hour_hand_and_minute_hand
At 3:00 (1500 hours) on a clock, the hour hand is pointing directly at the 3 and the minute hand is pointing at the 12. To find the angle between the hands, we can use the formula: |(30*H) - ((11/2)M)|, where H is the hour and M is the minute. Plugging in the values, we get |(303) - ((11/2)*0)| = |90 - 0| = 90 degrees. Therefore, the angle between the hands of the clock at 1500 hours is 90 degrees.
39o26' (to the nearest minute) Explanation: Let the angle = θ sinθ = 0.6352 To find the angle of sinθ, you must apply sin-1 to sinθ. sin-1θ = 39o26'5.35"
Any angle between 0 and 180 degrees or 0 and pi radians.
explement of the angle or conjugate of an angle
Oh, dude, you're hitting me with the clock riddles now? Alright, let's see... The hour hand moves 30 degrees every hour, so it'll be at 90 degrees four times between 9am and 3pm. The minute hand will be at 90 degrees once every hour, so that's five times total. So, like, five times in total, I guess.
To find the angle between two vectors, you need to use this form: a ∙ b / (|ab|) = cos(θ) θ = arccos(a ∙ b / (|ab|)) where a and b are vectors. Compute the dot product and the norm of |a| and |b|. Then, compute the angle between the vectors.
The angle of depression of a point is the angle between the line joining that point and the point of observation and the horizontal from the point of observation.
The angle of incidence is the angle formed between an incident ray and the normal to a surface at the point of incidence.
You have to convert them to Polar Points or the Azimuth points and use the angle difference.
i have no idea son