#include <stdio.h>int main(){ int num1, num2, max; printf("Enter two positive integers: "); scanf("%d %d", &num1, &num2); max=(num1>num2) ? num1 : num2; while(1) { if(max%num1==0 && max%num2==0) { printf("LCM of %d and %d is %d", num1, num2,max); break; } ++max; } return 0;}
You need at least two numbers to find an LCM.Two or more numbers are needed to find the Lcm
Two or more numbers are needed to find their LCM
Two or more numbers are needed to find their LCM
Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.
No. You can only find the LCM of at least two numbers, prime or otherwise. The LCM of any two prime numbers is their product.
You need at least two numbers to find an LCM.
Two or more numbers are needed to find the LCM
You need at least two numbers to find an LCM.
You need at least two numbers to find an LCM.
The product of the GCF and the LCM of two numbers is equal to the product of the original two numbers. Multiply the GCF and the LCM. The original two numbers will be another factor pair of that total. Find the factor pair that has that GCF and LCM.
You need at least two numbers to find an LCM.
Two or more numbers are normally needed to find the LCM