Q: How do you find two numbers if HCF and LCM are known?

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hcf: 1 lcm: 112,038

Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a

No. The LCM MUST be a multiple of the HCF.

hcf or gcf. first write the numbers the number can be multiplied to get it,you will have more than one or two numbers and when you see you have the number in a row then look for the highest number in all row .LCM do same as hcf but the numbers you got just multiply.try 2,4,16,24,48 you must get for LCM get 144 and for hcf or gcf you must get 24.

LCM = product/HCF so product = LCM/HCF in this case 380/16 which is 23.75, so the answer to your question is no.

Related questions

You cannot. The numbers 2 and 12 have hcf = 2 and LCM = 12 The numbers 4 and 6 also have hcf = 2 and LCM = 12 So if you just knew the hcf and LCM you would not know which of the two was the required pair.

if the product of two numbers is 810 if there hcf is 9 find Lcm

The HCF is always a factor of the LCM of two numbers. The HCF is a factor of both the numbers which are factors of their LCM. Thus the HCF is also a factor of the LCM of the two numbers.

HCF of 17 and 68 is 17 ..( Lowest Prime factor ) LCM Of 102 and 476 is 7*2^2*3*17 which is 1428 .. ==> Sum of HCF and LCM are 1428+17= 1445 .

To find the LCM, you multiply the numbers together and then divide by the HCF. In this case, we don't know the numbers, but we have the HCF (13) and we have the product of the numbers (1690). Thus all you do is divide 1690 by 13 to get: 1690/13 = 130 And thus the LCM of two numbers whose hcf is 13 and product is 1690 is 130.

hcf: 1 lcm: 112,038

Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a

Divide the product of the original numbers by 108, the LCM. The result will be the GCF.

220

No. The LCM MUST be a multiple of the HCF.

384

Two or more numbers are needed to solve for HCF or LCM.