C program to find the given number is Adam number?

Answer 1

1. /* To check whether a number is Adam number or not */
2. #include
3. #include
4. void main()
5. {
6. int i,n,n1,n2,ns,r,rev=0,nr=0,nrs;
7. clrscr();
8. printf("Enter a no.n");
9. scanf("%d",&n);
10. ns=n;
11. n1=n*n;
12. n2=n1;
13. while(n2>0)
14. {
15. r=n2%10;
16. n2=n2/10;
17. rev=rev*10+r;
18. }
19. while(ns>0)
20. {
21. r=ns%10;
22. ns=ns/10;
23. nr=nr*10+r;
24. }
25. nrs=nr*nr;
26. if (rev==nrs)
27. printf("%d is an Adam no.n",n);
28. else
29. printf("%d is not an Adam no.n",n);
30. getch();
31. }
32. }

Answer 2

• #include
• #include
• void main()
• {
• int i,n,n1,n2,ns,r,rev=0,nr=0,nrs;
• clrscr();
• printf("Enter a no.n");
• scanf("%d",&n);
• ns=n;
• n1=n*n;
• n2=n1;
• while(n2>0)
• {
• r=n2%10;
• n2=n2/10;
• rev=rev*10+r;
• }
• while(ns>0)
• {
• r=ns%10;
• ns=ns/10;
• nr=nr*10+r;
• }
• nrs=nr*nr;
• if (rev==nrs)
• printf("%d is an Adam no.n",n);
• else
• printf("%d is not an Adam no.n",n);
• getch();
• }
• }

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