pH= -log = 1.59
The Ka for the dissociation of HNO2 is 4.5 x 10^-4. This value represents the equilibrium constant for the reaction of HNO2 dissociating into H+ and NO2-.
Use the Henderson-Hasselbalch equation:[H+] = Ka * [HA] / [A-]where[HA] = concentration HNO2 (acid) and[A-] = concentration NO2- (base) andKa = 4.7*10-4Filling in and calculating: [H+] = Ka * [HA] / [A-] = (4.7*10-4) * (0.15) / (0.20) = 3.5*10-4 ,so :pH = -log[H+] = -log(3.5*10-4) = 3.45
add 4 parts water per part solution
The mass of a 10 mmol solution will depend on the molar mass of the solute. To calculate the mass, multiply the number of moles (10 mmol) by the molar mass of the solute in grams/mole.
To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).
Base. -log(3.0 X 10^-10) = pH of 9.5
Molarity=moles of solute/liters of solvent=5mol/10L=0.5M
To calculate the mass of medication in the solution, multiply the volume of the solution (500 ml) by the concentration of the medication (10%). Convert the percentage to a decimal by dividing by 100 (10% = 0.10). So, 500 ml x 0.10 = 50 grams of medication in 500 ml of a 10% solution.
To calculate the molarity of a solution, you would need to divide the number of moles of solute (in this case, 10 mol of NaCl) by the volume of solution in liters (in this case, 200 L). Molarity = moles of solute / liters of solution So, Molarity = 10 mol / 200 L = 0.05 M.
To prepare a 10 mm solution, you would dilute the 4 M stock solution. Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (4 M), V1 is the volume of stock solution needed, C2 is the desired final concentration (10 mM), and V2 is the final volume of the solution. Calculate the volume of stock solution needed to achieve the desired concentration, then add solvent (usually water) to reach the final volume.
Clue: He didn't laugh at the boss' jokes because he was…Answer: Musty, quota, elicit, lading, and QUITTING.
Yes, 0.02 * 0.02 has the same product as 0.2 * 0.002. (They both equal .0004). .2 = .02 * 10, and .002 = .02 / 10, so .2 * .002 = .02 * 10 * .02 / 10 = .02 * .02 * (10 / 10) = .02 * .02