0
pH= -log = 1.59
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What is Ka for HNO2(aq) H (aq) NO2-(aq)?
The Ka for the dissociation of HNO2 is 4.5 x 10^-4. This value represents the equilibrium constant for the reaction of HNO2 dissociating into H+ and NO2-.
Nitrous acid has a Ka of 4.7x10-4. What is the pH of a buffer solution containing 0.15 M HNO2 and 0.20 M NO2?
Use the Henderson-Hasselbalch equation:[H+] = Ka * [HA] / [A-]where[HA] = concentration HNO2 (acid) and[A-] = concentration NO2- (base) andKa = 4.7*10-4Filling in and calculating: [H+] = Ka * [HA] / [A-] = (4.7*10-4) * (0.15) / (0.20) = 3.5*10-4 ,so :pH = -log[H+] = -log(3.5*10-4) = 3.45
What is ka for HNO2(aq) H plus (aq) plus NO2-(aq)?
The acid dissociation constant (Ka) for the dissociation of nitrous acid (HNO2) into hydrogen ions (H⁺) and nitrite ions (NO2⁻) can be expressed with the equation: [ K_a = \frac{[H^+][NO_2^-]}{[HNO_2]} ] This equilibrium constant quantifies the strength of HNO2 as an acid; a larger Ka value indicates a stronger acid, meaning it dissociates more completely in solution. For HNO2, the Ka is approximately 4.5 × 10⁻⁴ at 25°C, indicating it is a weak acid.
How much water added to convert a 10 percent solution to 02 percent solution?
add 4 parts water per part solution
What is the mass of 10 mmol solution?
The mass of a 10 mmol solution will depend on the molar mass of the solute. To calculate the mass, multiply the number of moles (10 mmol) by the molar mass of the solute in grams/mole.
How do make a percent sucrose solution?
To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).
What is the pOH of a solution with OH- 1.410-13?
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that [OH⁻] = 1.41 × 10⁻¹³, calculate the pOH: pOH = -log(1.41 × 10⁻¹³) ≈ 12.85. Therefore, the pOH of the solution is approximately 12.85.
A solution for which OH- equals 3.0 x 10 to the negative 10 is classified as an acid basic or neutral and how to calculate?
Base. -log(3.0 X 10^-10) = pH of 9.5
Calculate the concentration of a solution when 5 moles of solute is dissolved to make 10 l of solution?
Molarity=moles of solute/liters of solvent=5mol/10L=0.5M
How many grams of medication will 500 ml of a 10 percent solution contain?
To calculate the mass of medication in the solution, multiply the volume of the solution (500 ml) by the concentration of the medication (10%). Convert the percentage to a decimal by dividing by 100 (10% = 0.10). So, 500 ml x 0.10 = 50 grams of medication in 500 ml of a 10% solution.
What would you be need to do to calculate the molarity of 10 mol of NaCl in 200?
To calculate the molarity of a solution, you would need to divide the number of moles of solute (in this case, 10 mol of NaCl) by the volume of solution in liters (in this case, 200 L). Molarity = moles of solute / liters of solution So, Molarity = 10 mol / 200 L = 0.05 M.
How do you prepare 10 mm solution with 4 m stock solution?
To prepare a 10 mm solution, you would dilute the 4 M stock solution. Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (4 M), V1 is the volume of stock solution needed, C2 is the desired final concentration (10 mM), and V2 is the final volume of the solution. Calculate the volume of stock solution needed to achieve the desired concentration, then add solvent (usually water) to reach the final volume.
