Wiki User
∙ 14y agoadd 4 parts water per part solution
Wiki User
∙ 14y ago98 mL
75 litres
There is 1 gallon of 10% solution...There is 0% saline in water...The equation is (0.1)(1) + 0x = 0.02 (x+1)...Answer is: 4 gallons. Hope I helped!!:)
195 grams.
684 ml
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
To convert the solution from m percent salty to 2m percent salty, you need to add m/2 grams of salt. This will ensure that the ratio of salt to water in the solution is doubled, resulting in a 2m percent salty solution.
4 litres
98 mL
75 litres
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
Dissolve 15 g salt in 100 mL water.
The initial amount of KCl in the solution is 12mL (12% of 100mL). When 200mL of water is added, the total volume becomes 300mL. You would then divide the initial amount of KCl (12mL) by the total volume (300mL) and multiply by 100 to get the final concentration of KCl in the solution.
To make a 15.00% by mass aqueous solution with NaCl, the mass of NaCl is 255.0g. This means that 15.00g of NaCl is present in every 100.00g of solution. To find the mass of water needed, first calculate the mass of NaCl in the final solution, then subtract this amount from the total mass of the solution (water + NaCl).
There is 1 gallon of 10% solution...There is 0% saline in water...The equation is (0.1)(1) + 0x = 0.02 (x+1)...Answer is: 4 gallons. Hope I helped!!:)