add 4 parts water per part solution
98 mL
There is 1 gallon of 10% solution...There is 0% saline in water...The equation is (0.1)(1) + 0x = 0.02 (x+1)...Answer is: 4 gallons. Hope I helped!!:)
195 grams.
684 ml
2 gallons.
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
4 litres
To convert the solution from m percent salty to 2m percent salty, you need to add m/2 grams of salt. This will ensure that the ratio of salt to water in the solution is doubled, resulting in a 2m percent salty solution.
98 mL
To convert a 10% sugar solution into a 5% sugar solution, you would need to dilute the original solution by adding a calculated amount of water. For example, to create 1 liter of 5% sugar solution from a 10% solution, you would mix 500ml of the 10% solution with 500ml of water.
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
Dissolve 15 g salt in 100 mL water.
There is 1 gallon of 10% solution...There is 0% saline in water...The equation is (0.1)(1) + 0x = 0.02 (x+1)...Answer is: 4 gallons. Hope I helped!!:)
195 grams.
To determine the mass of the solution, we need to calculate the total mass of the solution when 81g of glucose is added. Since the solution is 15.0% glucose by mass, the remaining 85.0% is water. Therefore, the total mass of the solution can be calculated using the mass of glucose added and the percentage of water. This would result in a total mass of solution greater than 81g due to the addition of water to dissolve the glucose.