To get molarity, you bring it up to a litre, and do the same factor to the number of moles. i.e. 0.25/150*1000 will give you 1.667 molar.
.025"
If u mean 25 ounces, there should be 625 grams.
This volume is 6,197 399 5 at 25 0C.
First write the balanced chemical equation for this reaction CaCO3+2HCl-->CaCl2+H2O+CO2 It is clear from this equation that one mol of HCl can react with half a mol of CaCO3. Thus, one half of .025 mols CaCO3 will react with .025 mols HCl. That makes .0125 mols CaCO3.
density or specific weight ( it is hard to explain but gravity/density of a given massA) Water is taken as standard with l.o in fresh water, and l.025 for Saline- as is marked on depth gauges on Submarines. adjust for density. Platinum and other rare earths have a very heavy specific gravity- as well suits there dense structure. on the other hand aluminum is very light.
1.25 Solution Method: 1. Convert 2.5% to decimal: 2.5 / 100 = .025 2 Compute answer: 50 * .025 = 1.25
.025 percent Solution Method: 250 ppm = the ratio 250:1,000,000 = the fraction 250/1,000,000 = the decimal value 0.00025 = the percentage .025 (i.e. 0.00025 * 100)
025 is the same as 25 which is greater than 5
It is: .025 times 80 = 2
I assume you mean 5 and 025 (but I'll answer for.025 also). 5 milligrams is larger than 0.025mg. However 5mg is smaller than 025 milligrams.
.025 is thicker than .012
0.0001
No. 025 cents is 25 cents.
95 is greater than 025
The only information you've given is you want to know moles and how many Liters there are. To calculate, you need to know what you are preparing(i.e., N2, AgNO3, etc.), and it's Molarity(M). Here's an example: How many moles of silver nitrate are needed to prepare 250mL of standard 0.100M silver nitrate solution? Note: M = moles of solute(stuff) / volume of solution(L) = # moles / L So, ?/250mL=.1M First we use dimensional analysis to convert mL to L. 250mL x 10-3 L / 1 mL = .25L Since we know M=moles/L, we can take the Molarity and put it in moles/L form. .10M = .10 mol/L Finally, .10 mol/L x .25L = .025 mol AgNO3 We can make a general assumption for your question and say the M is standard .100M. .10M = .10 mol/L .10 mol/L x 48L = 4.8 moles
They are: .025, 0.25, 2.5 and 25
0.05, 0.5, 5.2 and 025.