The question does not make sense.
#include<stdio.h> #include<conio.h> int main(void) { float a,b,c=0, d=0, e=0,f=0; printf("Please enter two numbers:\n"); scanf("%f %f", &a, &b); c=a+b; d=a-b; e=a*b; f=a/b; printf("The sum of %f and %f is :%f\n", a,b,c); printf("The subtraction of %f and %f is :%f\n", a,b,d); printf("The multiplication of %f and %f is :%f\n", a,b,e); printf("The division of %f by %f is :%f\n",a,b,f); getch(); }
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
any number (n) added to zero equals that same number (n). n + 0 = n
Certainly! Here are some key formulas and properties related to exponents and identity elements: Exponents Formulas: *Product of Powers:* [ a^m \cdot a^n = a^{m+n} ] When multiplying two exponents with the same base, you add the exponents. *Quotient of Powers:* [ \frac{a^m}{a^n} = a^{m-n} \quad (\text{for } a \neq 0) ] When dividing two exponents with the same base, you subtract the exponents. *Power of a Power:* [ (a^m)^n = a^{m \cdot n} ] When raising an exponent to another power, you multiply the exponents. *Power of a Product:* [ (ab)^n = a^n \cdot b^n ] When raising a product to a power, you raise each factor to the power. *Power of a Quotient:* [ \left( \frac{a}{b} \right)^n = \frac{a^n}{b^n} \quad (\text{for } b \neq 0) ] When raising a quotient to a power, you raise both the numerator and the denominator to the power. *Zero Exponent:* [ a^0 = 1 \quad (\text{for } a \neq 0) ] Any non-zero number raised to the power of zero is 1. *Negative Exponent:* [ a^{-n} = \frac{1}{a^n} \quad (\text{for } a \neq 0) ] A negative exponent indicates the reciprocal of the base raised to the opposite positive exponent. Identity Elements: *Additive Identity:* [ a + 0 = a \quad \text{and} \quad 0 + a = a ] The number 0 is the additive identity because adding 0 to any number ( a ) leaves ( a ) unchanged. *Multiplicative Identity:* [ a \times 1 = a \quad \text{and} \quad 1 \times a = a ] The number 1 is the multiplicative identity because multiplying 1 by any number ( a ) leaves ( a ) unchanged. These formulas and properties are fundamental in algebra and are used frequently in solving equations and simplifying expressions. If you need further details or examples, please let me know!
Given a number n, the addititive inverse is -n since n+(-n)=0. Howevern+(-n) is the same as n-n which is 0 also.SO adding the additive inverse it the same as subtracting.
For any number n, n + 0 = 0 + n = n All you need to do is to substitute any number of your choice, for n.
It is a tautological description of one of the basic properties of numbers used in the branch of mathematics called Analysis: Property 2: there exists an additive identity, called 0; for every number n: n + 0 = 0 + n = n. Property 3: there exists an additive inverse, of every number n denoted by (-n) such that n + (-n) = (-n) + n = 0 (the additive identity).
Any number to the power '0' equals '1'. Proof ; Let a^(n) = b Then dividing a^(n) / a^(n) = b/b a^(n-n) = b/b a^(0) = 1
It is the additive identity property of zero. (n+0=n)
#include<stdio.h> int main() { int num[]={1,2,3,4,5,6}; int i,temp; for(i=0;i<=5;i=i+2) { temp=num[i]; num[i]=num[i+1]; num[i+1]=temp; } for(i=0;i<=5;i=i+2) printf(''%d",num[i]); return 0; }
It is the property of n as the additive identity.
The inverse operation of addition would be subtraction. Example : 2 + 3 = 5 Performing the inverse operation yields the original number. Example : 5 - 3 = 2