Best Answer

<html>

<head>

<Script Language="JavaScript">

var a,n,b=0,t;

n=parseInt(window.prompt("enter n","0"));

t=n;

while(n>0)

{

a=n%10;

b=b+a*a*a;

n=n/10;

}

if(b==t)

{

document.writeln("Armstrong no");

}

else

{

document.writeln("Not an Armstrong no");

}

</script>

</head>

</html>

Q: Program to check whether the given number is an Armstrong number?

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write a c++program by using if statement to read a number and check whether it is positive or negative

45

if it's square root is an integer, it is a square number.

Where do you get that idea? Who doesn't recognize the number 13? Better check whether Canada does, or does not, recognize this number, instead of just assuming such an improbable situation.Where do you get that idea? Who doesn't recognize the number 13? Better check whether Canada does, or does not, recognize this number, instead of just assuming such an improbable situation.Where do you get that idea? Who doesn't recognize the number 13? Better check whether Canada does, or does not, recognize this number, instead of just assuming such an improbable situation.Where do you get that idea? Who doesn't recognize the number 13? Better check whether Canada does, or does not, recognize this number, instead of just assuming such an improbable situation.

Type your answer here... i think we should first enter 1 number then check it

Related questions

write a c++program by using if statement to read a number and check whether it is positive or negative

/*Program to find whether given no. is Armstrong or not. Example : Input - 153 Output - 1^3 + 5^3 + 3^3 = 153, so it is Armstrong no. */ class Armstrong{ public static void main(String args[]){ int num = Integer.parseInt(args[0]); int n = num; //use to check at last time int check=0,remainder; while(num > 0){ remainder = num % 10; check = check + (int)Math.pow(remainder,3); num = num / 10; } if(check == n) System.out.println(n+" is an Armstrong Number"); else System.out.println(n+" is not a Armstrong Number"); } }

import java.io.*; public class Jerry { public static void main(String as[]) throws IOException { int k=Integer.parseInt(as[0]); int n=k; int d=0,s=0; while(n>0) { d=n%10; s=s+(d*d*d); n=n/10; } if(k==s) System.out.println("Armstrong number"); else System.out.println("not Armstrong number"); } }

write a program in C to check whether a given number is apalindrome or not

8086 assembly language program to check wether given number is perfect or not

Going through a program on paper to check whether it has errors.

45

To write a C program to determine if something is odd or even you need to be a programmer. To write a program in C is complicate and only done by programmers.

The program is here guys.......... //Finding whether the given number is perfect or not //Starts here #include<stdio.h> void main() { int i=1,temp=0,number; scanf("%d",&number); while(i<=number/2){ if(number%i==0) temp+=i; i++; } if(temp==number) printf("Its a perfect number"); else printf("Its not a perfect number"); } //ends here

if it's square root is an integer, it is a square number.

Where do you get that idea? Who doesn't recognize the number 13? Better check whether Canada does, or does not, recognize this number, instead of just assuming such an improbable situation.Where do you get that idea? Who doesn't recognize the number 13? Better check whether Canada does, or does not, recognize this number, instead of just assuming such an improbable situation.Where do you get that idea? Who doesn't recognize the number 13? Better check whether Canada does, or does not, recognize this number, instead of just assuming such an improbable situation.Where do you get that idea? Who doesn't recognize the number 13? Better check whether Canada does, or does not, recognize this number, instead of just assuming such an improbable situation.

Use the Exception class and type converters.