Watts = Current x Voltage x Power Factor
If you are talking about 120 VAC and a pure resistive load (Where Power Factor = 1) then the steady state current is about 8.3 Amps. So you are okay.
If you had a conductive load with a Power Factor of .5 then the current would double. The steady state current should be no more than 80% of the breaker rating. Therefore, the steady state current should be less than or equal to 16 amps.
No. 20 amps at 120 volts will handle a maximum of 2400 watts. And you should never continuously load a 20 amp 120 volt circuit to no more than 1920 watts.
2.3 kw per hour on a 110-120 volt circuit.
The unit of power is expressed in watts, and the product of current (Amps) and voltage (volts) is power there fore if you multiply the amps and the volts give watts. so 20 x 240 will give you a 4800 watts of power.
250 watts divided by 12 volts = amps or around 20 amps
Watts = Amps * Volts Watts = 20 amps * 100 Volts Watts = 2000 2,000 Watts or 2k Watts
Watts = Amps * Volts Watts = 20 amps * 100 Volts Watts = 2000 2,000 Watts or 2k Watts
No. A 120 volt 15 amp service will handle a maximum of 1,800 watts. Even a 20 amp service will only handle 2400 watts and that is at max load which you should never load on a 20 amp circuit. You will need a 30 amp 120 volt or 240 volt service for 2400 watts.
Twenty amps is zero watts. You are missing one value. W = Amps x Volts. <<>> It depends on the resistance and the draw current in the electrical circuit.
Zero. Watts is the product of Amps x Volts. As you can see an amperage value is needed. Voltage = Watts/Amps. Volts = 200/? 20 volts
UPS batteries are typically rated at how many ampere hrs they can supply. IF your 20 Watt device is supplied by 120V then it draws 1/6 amps. (Watts = Amps * Volts for a resistive load). If your UPS were rated for 1 A Hr you could power your device for 6 hours.
it would depend upon the current. Power (watts) = I (current in amps) x E (voltage). 2 watts = 15 amps x .133 volts 2 watts = 20 amps x .10 volt
The kilowatt power draw of the electric furnace can be calculated using the formula: Power (kW) = Current (A) x Voltage (V) / 1000. Plugging in the values (20 A and 240 V) into the formula, we get: Power = 20 A x 240 V / 1000 = 4.8 kW. Therefore, the electric furnace has a power draw of 4.8 kilowatts.