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What is the area of a rhombus with the diagonals lengths of 13 and 17 and the base length of 7.6?
110.5 sq units
What is the area of a rectangle with a perimeter of 24?
Any positive value upto 36 square units. A 6x6 square will have the maximum area of 36 sq units; a 5x7 rectangle will have an area of 35 sq units, and the area will be reduced as you reduce one of the measures and increase the other so that their sum remains 12 units so that the perimeter is 24 units. 1x11 will be 11 sq units 0.1x11.9 will be 1.19 sq units 0.01x11.99 will be 0.1199 sq units 0.001x11.999 will be 0.011999 sq units, etc.
What is the area of a figure with a perimeter of 36?
Any area you want greater than 0 square units and less than or equal to 324/π sq units ≈ 103.13 sq units.
How many sq yards in a 36 x 18'?
It depends on the units used for 36: inches, feet, yards, miles, etc
How many sq yards are in 690 sq inches?
1 sq yard = 36*36 sq inches So 690 sq inches = 690/(36*36) = 0.5324 sq yards.
What is 36 x 56 x 25 in sq ft?
An impossibility because the dimensions given can only be measured in cubic units.
How many 36 x 36 tiles will you need to cover 1098 sq ft?
12" = 1 foot 36" = 3 ft 36" x 36" = 9 sq ft 1,098 sq ft/9 sq ft per tile = 122 tiles
What is area of rhombus with diagonals of 8ft and 6ft?
48 sq ft.
What is the area of a perimeter of 2.4?
Any positive value upto 0.36 square units. A 0.6 x 0.6 square will have the maximum area of 0.36 sq units; a 0.5 x 0.7 rectangle will have an area of 0.35 sq units, and the area will be reduced as you reduce one of the measures and increase the other so that their sum remains 1.2 units so that the perimeter is 2.4 units. 0.1x1.1 will be 0.11 sq units 0.01x1.19 will be 0.0119 sq units 0.001x1.199 will be 0.001199 sq units 0.0001x1.1999 will be 0.00011999 sq units, etc.
How many one meter sq fit inside a sq with an area of 36 sq meters?
36 x 1 metre squares.
Change 1 sq yard into sq inches?
1 sq yard = 1 yd* 1 yd = 36 inches * 36 inches = 1296 sq inches.
What is the height x of a trapezoid if its area is 234 square units and the two parallel sides are 20 and 32 units long?
area = ½ × sum_of_parallel_sides × perpendicular_distance_between_them → 234 sq units = ½ × (20 units + 32 units) × x → x × 26 units = 234 sq units → x = 234 sq units ÷ 26 units → x = 9 units
