110.5 sq units
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
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If you are wanting the area of a rhombus that have diagonals which lengths are 3 and 12, then the area is 18 square units.
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Half the product of the lengths of its diagonals. A=1/2(d1*d2)
The are different formulae for its perimeter, area, lengths of diagonals, angle and these depend on what information is provided.
Area = length*perpendicular height or 0.5*the product of its diagonals
There is no specific "formula." If you want the area of a rhombus, that is just A = bh/2 or (1/2)xy where x and y are the lengths of the diagonals.
The area ( A ) of a rhombus can be calculated using the formula ( A = \frac{1}{2} \times d_1 \times d_2 ), where ( d_1 ) and ( d_2 ) are the lengths of the diagonals. The perimeter ( P ) of a rhombus is given by the formula ( P = 4s ), where ( s ) is the length of one side.
The diagonals of a rhombus cannot be the same size.