No, By the triangle inequality theorem (or something like that), the sum of any two sides of a triangle must add up to be greater than the third side. 8+7
Area of triangle: 0.5*12*14*sin(134.6183417) = 16 square units rounded to the nearest whole number
for perimeter, just add all the side lengths 16+16+14+14=60 inches
Yes
The third side of a triangle must be greater than the absolute difference of the two given sides and less than the sum of the two given sides. In this case, the third side must be greater than |7-9| = 2 and less than 7+9 = 16. Therefore, the possible lengths for the third side of the triangle could be any value greater than 2 and less than 16.
No because it does not comply with Pythagoras' theorem.
Yes 652 = 162+632
Does 652 = 162 + 632? Yes, so it is a Pythagorean triangle.
If you mean sides of 10, 12 and 16 then yes a triangle be constructed because the sum of its 2 smaller sides is greater than its longest side.
It's 6,40312. 4²+5²= hypotenuse ² 16+25=hypotenuse ² 41=hypotenuse ² |√ 6,40312=hypotenuse
One pair of corresponding sides of a triangle that are similar to triangle ABC are 6 inches and 8 inches. However, there are multiple answers to this question.
Any two figures that total 17 ie from 1 x 16 up to 8 x 9
No. But they can be the lengths (not leangths!) of the three sides.