Q: Can 16 30 and 34 be a triangle leangth?

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Yes because they comply with Pythagoras' theorem.

If its a right angle it will be 34 units in length because it complies with Pythagoras' theorem.

The diagonal will be the hypotenuse of a right triangle with legs 30 and 34 feet So its length is the square root of (34^2+ 30^2 )

16

To find the length of the hypotenuse of a right triangle, use the Pythagorean Theorem: A2 + B2 =C2Where A and B are the lengths of the legs, and C is the length of the hypotenuse.(16)2+(30)2=C2C=sqrt(256+900)C=34

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Yes because they comply with Pythagoras' theorem.

To test use PYTHAGORAS ; h^2 = a^2 + b^2 34' is the longest side (h) , hence 34^(2) = 1156 a & b are 16 & 30 Hence 16^() + 30^(2) = 256 + 900 = 1156 , which equatres with 34^(2) . Thereby satisfies the Pythagorean Equation. Hence it is a Right angled triangle. So the sides 16,30, & 34 form a right triangle.

A triangle whose sides are 16, 30, and 35 in length is not a right triangle, becausethe square of the length of the longest side is not equal to the sum of the squaresof the lengths of the other two sides.But if the 35 were a 34 instead, then it wouldbe.

If its a right angle it will be 34 units in length because it complies with Pythagoras' theorem.

No

The diagonal will be the hypotenuse of a right triangle with legs 30 and 34 feet So its length is the square root of (34^2+ 30^2 )

34

4x2-30 = 34 4x2 = 34+30 4x2 = 64 x2 = 16 x = 4

16

To find the length of the hypotenuse of a right triangle, use the Pythagorean Theorem: A2 + B2 =C2Where A and B are the lengths of the legs, and C is the length of the hypotenuse.(16)2+(30)2=C2C=sqrt(256+900)C=34

A right angled triangle cannot have one angle of 34 and another of 16 since the three angles (including the right angle) must add to 180 degrees.

The length is 32. Since an isosceles triangle is symmetrical, the height divides it into two right triangles. The hypotenuse of one of these triangles is 34, one of the legs is 30 (the height), and the other leg is half of the base, which we'll call x. Using the Pythagorean Theorem, we know x^2+30^2=34^2, or x^2+900=1156. This gives us x^2=256, or x=16 (it could also be -16, but this is absurd because it's a length). We said x was half the base, so the base itself is 2x=2*16=32.